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sweet-ann [11.9K]
2 years ago
5

Franny drew a diagram to compare images produced by concave and convex lenses.

Physics
2 answers:
Zina [86]2 years ago
8 0

Answer:

B. Virtual

Good Luck!

Tasya [4]2 years ago
6 0

Answer:

Virtual

Explanation:

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Nuclear decay occurs according to first-order kinetics. Cobalt-60 decays with a rate constant of 0.131 years−1. After 5.00 years
alexandr402 [8]

Answer : The original mass of the sample was 0.581 grams.

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 0.131\text{ years}^{-1}

t = time passed by the sample = 5.00 years

a = original or initial amount of the reactant  = ?

a - x = amount left after decay process = 0.302 g

Now put all the given values in above equation, we get

5.00\text{ years}=\frac{2.303}{0.131\text{ years}^{-1}}\log\frac{a}{0.302g}

a=0.581g

Therefore, the original mass of the sample was 0.581 grams.

8 0
2 years ago
Liquid X of volume 0.5m3 and density 900kgm-3 was mixed with liquid Y of volume 0.4m3 and density 800kgm-3. What was the density
masha68 [24]

Answer:

Density of the mixture = 855.56kgm-3

Explanation:

Density = Mass / Volume

Volume of Liquid X = 0.5m³

Density of Liquid X = 900kgm-3

Mass of Liquid X = Density × Volume

= 900kgm-3 × 0.5m³ = 450kg

Volume of Liquid Y = 0.4m³

Density of Liquid Y = 800kgm-3

Mass of Liquid Y = Density × Volume

= 800kgm-3 × 0.4m³= 320kg

As X and Y are mixed, we add their masses and volumes together:

Mass = 770kg

Volume = 0.9m³

Now we can find the density of the mixture:

Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)

8 0
2 years ago
Desde que altura debes de lanzar una canica de 50g para que adquiera una energia de 100j
AnnZ [28]

Answer:

204 m

Explanation:

When the marble is dropped from a certain height, its gravitational potential energy converts into kinetic energy. So the kinetic energy gained is equal to the variation of gravitational potential energy:

\Delta U=mg\Delta h

where

m is the mass of the marble

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h is the change in height

In this problem, we have

m = 50 g = 0.05 kg

\Delta U = 100 J

Solving the formula for \Delta h, we find the necessary height from which the marble should be dropped:

\Delta h = \frac{\Delta U}{mg}=\frac{100}{(0.05)(9.8)}=204 m

7 0
3 years ago
An object began moving at the starting point (0,0) on the graph. The average speed of the object for the entire trip of 5.0 hour
AURORKA [14]
B 17


85 ÷ 5 would be the equation you do to solve
8 0
2 years ago
Read 2 more answers
Please help! I have another part to this too.
JulsSmile [24]

first one is true, there's no net force acting on it thats greater than another or making it unbalanced, if there was the object would be in some kind of motion

All scientist use meters, that way scientist can share information across country without needing to convert the data.

3. is air resistance

4. The large rock

5 0
2 years ago
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