Which sequence shows all the spectral colors of the visible light arranged in a decreasing order of their wavelength?

Physics

2 answers:

Ad libitum [116K]4 years ago

6 0

Correct answer choice is :

B) Red, orange, yellow, green, blue, indigo, and violet

Explanation:

A spectral color is a color that is extracted in a natural human by a single wavelength of light in the apparent rainbow, or by a comparatively narrow band of wavelengths, also recognized as monochromatic light. The combination of colors provided when the light is separated by a prism. Spectrum an indexed order of the elements of an radiation or wave. Electromagnetic rainbow the complete wavelength spectrum of electromagnetic waves.

Gnoma [55]4 years ago

5 0

The correct answer to this question is- B) Red, orange, yellow, green, blue, indigo, and violet.

EXPLANATION:

The visible region of the electromagnetic spectrum consists of white light with its constituent seven colors.

The constituent colors are known as violet, indigo, blue, green, yellow, orange and red respectively.

As per electromagnetic spectrum, these colors of light lie in the wavelength region ranging from 350 nm to 700 nm.

The wavelength of violet light is minimum, and is maximum for red light.

If we arrange these seven colors in the descending order of their wavelength, then they are arranged as follows-

Red > Orange > Yellow > Green > Blue > Indigo > Violet.

Hence, the perfect order is option B .

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The Moment of Inertia of the Disc is represented by $I = \frac{15}{32}\cdot M\cdot R^{2}$ . (Correct answer: A)

Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:

$I = I_{D} - I_{H}$ (1)

Where:

$I_{D}$ - Moment of inertia of the Disk.

$I_{H}$ - Moment of inertia of the Hole.

Then, this formula is expanded as follows:

$I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right)$ (1b)

Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole ( $m$ ):