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mylen [45]
3 years ago
6

Which sequence shows all the spectral colors of the visible light arranged in a decreasing order of their wavelength?

Physics
2 answers:
Ad libitum [116K]3 years ago
6 0

Correct answer choice is :


B) Red, orange, yellow, green, blue, indigo, and violet


Explanation:


A spectral color is a color that is extracted in a natural human by a single wavelength of light in the apparent rainbow, or by a comparatively narrow band of wavelengths, also recognized as monochromatic light. The combination of colors provided when the light is separated by a prism. Spectrum an indexed order of the elements of an radiation or wave. Electromagnetic rainbow the complete wavelength spectrum of electromagnetic waves.

Gnoma [55]3 years ago
5 0

The correct answer to this question is- B) Red, orange, yellow, green, blue, indigo, and violet.

EXPLANATION:

The visible region of the electromagnetic spectrum consists of white light with its constituent seven colors.

The constituent colors are known as violet, indigo, blue, green, yellow, orange and red respectively.

As per electromagnetic spectrum, these colors of light lie in the wavelength region ranging from 350 nm to 700 nm.

The wavelength of violet light is minimum, and is maximum for red light.

If we arrange these seven colors in the descending order of their wavelength, then they are arranged as follows-

      Red > Orange > Yellow > Green > Blue > Indigo > Violet.

Hence, the perfect order is option B .


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Answer:

B)

Explanation:

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Which of the following materials is necessary to stop an alpha particle? a. three feet of concrete c. single sheet of aluminum f
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Answer:

770m/s

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2 years ago
A spring with spring constant 15 N/m hangs from the ceiling. A ball is attached to the spring and allowed to come to rest. It is
olga nikolaevna [1]

Explanation:

It is given that,

Spring constant of the spring, k = 15 N/m

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Number of oscillations, N = 31

Time, t = 15 s

(a) Let m is the mass of the ball. The frequency of oscillation of the spring is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

Total number of oscillation per unit time is called frequency of oscillation. Here, f=\dfrac{31}{15}=2.06\ Hz

m=\dfrac{k}{4\pi^2f^2}

m=\dfrac{15}{4\pi^2\times 2.06^2}

m = 0.0895 kg

or

m = 89 g

(b) The maximum speed of the ball that is given by :

v_{max}=A\times \omega

v_{max}=A\times 2\pi f

v_{max}=0.075\times 2\pi \times 2.06

v_{max}=0.970\ m/s

v_{max}=97\ cm/s

Hence, this is the required solution.

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