Thick-walled steel or composite metal cylinder equipped with a control valve, pressure gauge, and nipple outlet for a high-pressure hose connection. in the fire service, these tanks contain compressed oxygen.
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What is a metal cylinder?</h3>
A thick-walled metal or steel composed or mixture cylinder consisting of many different cylindrically layers which are said to be orthotropic layers that are loaded by equal and uniform
The axisymmetric or unequal surface interacts andwith the help of piecewise uniform eigenstates the layers go with regard to the effect of fiber prestress on the final stress.
Therefore, thick-walled steel or composite metal cylinder equipped with a control valve, pressure gauge, and nipple outlet for a high-pressure hose connection. in the fire service, these tanks contain compressed oxygen.
Learn more about the metal cylinder, here:
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Answer: 3002.86kg
Explanation:
Hydraulic cylinder diameter =125mm
Ambient pressure =1bar
Pressure =2500kpa
Piston Mass (MP) =?
F|(when it moves upward )=PA=F|(when it moves downward) =PoA+Mpg
Po=1 bar=100kpa
A=(π/4)D^2=(π/4)*0.125^2=0.01227m^2
Mp=(P-Po) A/g=(2500-100)*1000*0.01227/9.80665
Mp=3002.86kg.
Your minimum selling price must be HIGHER THAN your variable costs
Answer:
1.737 kJ
Explanation:
Thinking process:
Step 1
Data:
Area of the shaft = 0.8 cm²
Combined mass of shaft and piston = (24.5 + 0.5) kg
= 25 kg
Piston diameter = 0.1 m
External atmospheric pressure = 1 bar = 101.3 kPa
Pressure inside the gas cylinder = 3 bar = 3 × 101.3 kPa
g = 9.81 m/s²
Step 2
Draw a free body diagram
Step 3: calculations
area of the piston = 0.0314 m²
Change in the elevation of the piston,
z =
=
= 0.82 m
Next, we evaluate the work done by the shaft:
= (1668) ( 0.082)
= 1. 37 kJ
Net area for work done = A (piston) - Area of shaft
=
= 77.7 cm²
= 0.007774 m²
Work done in overcoming atmospheric pressure:
Wₐ = PAZ
=101.3 kPa * 0.007774 * 0.82
= 0.637 kJ
total work = work done by shaft + work to overcome atmospheric pressure = 0.367 + 1.37
= 1.737 kJ Ans