Answer:

Explanation:
Let assume that changes in gravitational potential energy can be neglected. The fire hose nozzle is modelled by the Bernoulli's Principle:

The initial pressure is:

The speed at outlet is:

![v=\frac{(250\,\frac{gal}{min} )\cdot (\frac{3.785\times 10^{-3}\,m^{3}}{1\,gal} )\cdot(\frac{1\,min}{60\,s} )}{\frac{\pi}{4}\cdot [(1.125\,in)\cdot(\frac{0.0254\,m}{1\,in} )]^{2} }](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B%28250%5C%2C%5Cfrac%7Bgal%7D%7Bmin%7D%20%29%5Ccdot%20%28%5Cfrac%7B3.785%5Ctimes%2010%5E%7B-3%7D%5C%2Cm%5E%7B3%7D%7D%7B1%5C%2Cgal%7D%20%29%5Ccdot%28%5Cfrac%7B1%5C%2Cmin%7D%7B60%5C%2Cs%7D%20%29%7D%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%5Ccdot%20%5B%281.125%5C%2Cin%29%5Ccdot%28%5Cfrac%7B0.0254%5C%2Cm%7D%7B1%5C%2Cin%7D%20%29%5D%5E%7B2%7D%20%7D)

The initial pressure is:


Answer:
hello your question has a missing part below is the missing part
Consider the string length equal to 
answer : 2cos(2t) sin(2x) - 10cos(10t)sin(10x)
Explanation:
Given string length =
distorted function f(x) = 2sin(2x) - 10sin(10x)
Determine the wave formed in the string
attached below is a detailed solution of the problem
Answer:
Explanation:
The Turnaround time is the amount of time that elapses between the job arriving and completing. We assume that all jobs arrive at time 0, the turnaround time will simply be the time that they complete.
Round Robin:
we assume that the time quantum of the scheduler is 1 second.The table below gives a break down of which jobs will be processed during each time quantum. A asterisk(*) indicates that the job completes during that quantum.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
A B C D E A B C* D E A B D E A B D* E A B E A B* E A E A E* A A
C* = 8
D*=17
B*=23
E*=28
AVERAGE TURNAROUND = (8+17+23+28+30)/5 =106/5 = 21.2 MINUTES
B) PRIORITY SCHEDULING:
1-6 7-14 15-24 25-26 27-30
B E A C D
AVERAGETURNAROUND =(6+14+24+26+30)/5 = 100/5 = 20 MINUTES.
C)FCFS
1-10 11-16 17-18 19-22 23-30
A B C D E
AVERAGE TURNAROUND =(10+16+18+22+30)/5 = 96/5=19.2 MINTUES
D)SJF
1-2 3-6 7-12 13-20 21-30
C D B E A
AVERAGE TURNAROUND - (2+6+12+20+30)/5 =70/5 =14 MINUTES.