Answer:
The correct answer is option E.
Explanation:
Structures for the reactants and products are given in an aimage ;
Number of double bonds in oxygen gas molecule = 1
Number of double bonds in nitro dioxide gas molecule = 1
Number of single bond in in nitro dioxide gas molecule = 1
Number of triple bonds in nitrogen gas molecule = 1

![\Delta H=[2 mol\times \Delta H_{f,NO_2}]-[1 mol\times \Delta H_{f,N_2}-2 mol\times \Delta H_{f,O_2}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B2%20mol%5Ctimes%20%5CDelta%20H_%7Bf%2CNO_2%7D%5D-%5B1%20mol%5Ctimes%20%5CDelta%20H_%7Bf%2CN_2%7D-2%20mol%5Ctimes%20%5CDelta%20H_%7Bf%2CO_2%7D%5D)

(pure element)
(pure element )

The enthalpy of the given reaction is 15.86 kcal.
Answer:
For terrestrial animals, grazing is normally distinguished from browsing in that grazing is eating grass or forbs, and browsing is eating woody twigs and leaves from trees and shrubs. Grazing differs from true predation because the organism being grazed upon is not generally killed.
Explanation:
Answer:
a. 
b. K = 192.9
c. Products are favored.
Explanation:
Hello!
a. In this case, according to the unbalanced chemical reaction we need to balance HCl as shown below:

In order to reach 2 hydrogen and chlorine atoms at both sides.
b. Here, given the concentrations at equilibrium and the following equilibrium expression, we have:
![K=\frac{[HCl]^2}{[H_2][Cl_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BHCl%5D%5E2%7D%7B%5BH_2%5D%5BCl_2%5D%7D)
Therefore, we plug in the data to obtain:

c. Finally, we infer that since K>>1 the forward reaction towards products is favored.
Best regards!