Answer:
30 C
Explanation:
Given:
Current flowing in the circuit (I) = 50 A
Start-up time (t) = 0.60 s
Now, we know that, charge drawn in through a cross sectional area of the circuit is given as:
Where, 'q' is the amount of charge drawn, 'I' is the current and 't' is the start-up time.
Now, plug in 50 A for 'I', 0.60 s for 't' and solve for 'q'. This gives,
Therefore, the amount of charge drawn in the circuit at the start-up of the compressor of an air conditioner is 30 C.
Answer:
1. A solid can diffuse into a liquid, but a solid cannot diffuse into another solid.
3. A liquid can diffuse into another liquid.
4. A gas can diffuse into another gas.
Explanation:
When an object is in liquid or gas form, they can easily move and spread. This is because the molecules are packed loosely. Since they can move freely, diffusion on and into gas/liquid can be easily achieved.
Solid form can diffuse into liquid too. Seawater is mostly made of water and solid salt. But diffusing a solid into a solid is not possible since the molecule is tightly packed and barely moves. The diffusion might be happening, but at a really slow rate that we can assume it is not.
The normal force is equal in magnitude and opposite in direction to the weight of the student.
W = m · g = 60 kg · 10 m/s² = 600 N ( downward )
N = - 600 N
Answer:
B ) 600 N upward.
The most prominent roles of mitochondria<span> are to produce the energy currency of the cell, ATP </span>
Answer:
t = (ti)ln(Ai/At)/ln(2)
t = 14ln(16)/ln(2)
Solving for t
t = 14×4 = 56 seconds
Explanation:
Let Ai represent the initial amount and At represent the final amount of beryllium-11 remaining after time t
At = Ai/2^n ..... 1
Where n is the number of half-life that have passed.
n = t/half-life
Half life = 14
n = t/14
At = Ai/2^(t/14)
From equation 1.
2^n = Ai/At
Taking the natural logarithm of both sides;
nln(2) = ln(Ai/At)
n = ln(Ai/At)/ln(2)
Since n = t/14
t/14 = ln(Ai/At)/ln(2)
t = 14ln(Ai/At)/ln(2)
Ai = 800
At = 50
t = 14ln(800/50)/ln(2)
t = 14ln(16)/ln(2)
Solving for t
t = 14×4 = 56 seconds
Let half life = ti
t = (ti)ln(Ai/At)/ln(2)
