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gladu [14]
3 years ago
11

When a capacitor, battery, and resistor are connected in series, does the resistor affect the maximum charge stored on the capac

itor? Why or why not? What purpose does the resistor serve?
Physics
1 answer:
Vesnalui [34]3 years ago
8 0

Answer:

Absolutely No,resistance does not affect the maximum charge stored in capacitor as maximum charge stored is equal to Q=CV where V is voltage of battery

Resistor functions only to determine how quickly or lately capacitor will get charge

Explan

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A 900 N student runs up the stairs 3.5 m high in 12<br> seconds. How much POWER do they generate?
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4 0
3 years ago
A 3874-kg rollercoaster is brought to the top of a 42m hill in 40 seconds,then drops 28m before the next hill.
Ede4ka [16]

(a) The work required to get the coaster to the top of the first hill is  1,594,538.4 J.

(b) The power required to bring the train to the top of the first hill is 39,863.46 W.

(c) The energy lost when the coaster drops is 531,512.8 J.

(d) The left at the bottom is determined as 1,063,025.6 J.

<h3>Work done to bring the rollercoaster top of the hill</h3>

W = Fn x d = mgh

W = 3874 x 9.8 x 42

W = 1,594,538.4 J

<h3>Power dissipated in bringing the rollercoaster on top hill</h3>

P = Fv

P = Fd/t

P = W/t

P = 1,594,538.4 /40 = 39,863.46 W

<h3>Energy lost when the coaster drops</h3>

E = 1,594,538.4 - (3874 x 9.8 x 28)

E = 531,512.8 J

<h3>Energy left at the bottom</h3>

E = 3874 x 9.8 x 28 = 1,063,025.6 J

Learn more about energy here: brainly.com/question/13881533

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6 0
2 years ago
A force is represented by a ____ the choice of a ____ is necessary​
Vlad [161]

Answer:

a force is represented by a<u> vector </u>the choice of a <u>reference frame</u> is necessary​

Explanation:

3 0
3 years ago
What material of mass 39g,has a volume of 5cm^3
insens350 [35]
The material of density 7.8 g/cm³
4 0
3 years ago
A child is riding a merry-go-round that has an instantaneous angular speed of 12 rpm. If a constant friction torque of 12.5 Nm i
sammy [17]

Answer:

-0.25 rad/s^2

Explanation:

The equivalent of Newton's second law for rotational motions is:

\tau = I \alpha

where

\tau is the net torque applied to the object

I is the moment of inertia

\alpha is the angular acceleration

In this problem we have:

\tau = -12.5 Nm (net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)

I=50.0 kg m^2 is the moment of inertia

Solving for \alpha, we find the angular acceleration:

\alpha = \frac{\tau}{I}=\frac{-12.5 Nm}{50.0 kg m^2}=-0.25 rad/s^2

3 0
3 years ago
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