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Andrej [43]
3 years ago
9

The GPE of a 70kg person standing on a chair 1m off the ground is how many joules?

Physics
1 answer:
Artemon [7]3 years ago
8 0
GPE I am assuming is gravitational potential energy. I'll denote it as U for simplicity. 

U = mgy
U = (70kg)(9.81m/s^2)(1m) = 686.7J

U = 686.7J

Hope this helps!
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Please find the answer in the explanation

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14/7

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