a. We can calculate the amount of work by calculating the area under the graph.
first area (rectangular): 2.5 x 6 = 15
second area(trapezoid): 1/2 x (6+10) x 2.5 =20
total work done: 35 J
b. the force was first applied = 6 N
F = m.a
a = 6 : 3 = 2 m/s²
vf²=vi²+2as
vf²=6²+2.2.5
vf²=56
vf=7.5 m/s
The correct answer is:

Let's see why.
1 amu corresponds to the mass of the proton, which is:

if we convert this into energy, using Einstein equivalence between mass and energy, we find:

Now we can convert it into electronvolts:

So, 1 amu = 934 MeV. Therefore, 3 amu corresponds to 3 times this value:
Answer:
Nulo
Explanation:
Se o numero que aumenta for o mesmo que diminui, se torna nulo, pois nenhum passa a vencer o outro.
The work done is the same as the amount of energy increase. The formula for kinetic energy is 122
1
2
m
v
2
.
The initial KE of the car is 12(1000)×202=200,000
1
2
(
1000
)
×
20
2
=
200
,
000
joules.
The final KE of the car is 12(1000)×302=450,000
1
2
(
1000
)
×
30
2
=
450
,
000
joules.
The difference between these is the amount of work done: 450,000−200,000=250,000
450
,
000
−
200
,
000
=
250
,
000
joules.
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20
3
Answer:
0.85 A
Explanation:
the effective current is 0.85 A