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gtnhenbr [62]
4 years ago
13

38.2mm converted into cm

Chemistry
1 answer:
Alex4 years ago
8 0
1 mm ---------- 0.1 cm
38.2 mm ------ ?

38.2 x 0.1 / 1

= 3.82 cm
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. Use the following reaction to determine how much of each product would be released if 42 000 kg (42 tonnes) of methyl isocyana
fenix001 [56]

The amount of 1,3-dimethyl urea produced would be 32,458 grams or 32.458 kg while that of carbon dioxide would be 16,214 grams of 16.214 kg

<h3>Stoichiometric problem</h3>

From the equation of the reaction, the mole ratio of methyl isocyanate with the products is 2:1 respectively.

Mole of 42,000 kg of methyl isocyanate = 42000/57 = 736.84 moles

Equivalent mole of 1,3-dimethyl urea = 736.84/2 =368.42 moles

Equivaent mole of carbon dioxide = 736.84/2 =368.42moles

Mass of 368.42 moles 1,3-dimethyl urea = 368.42 x 88.1 = 32,458 grams or 32.458 kg

Mass of 368.42 moles of carbon dioxide = 368.42 x 44.01 = 16,214 grams of 16.214 kg

More on stoichiometric problems can be found here: brainly.com/question/14465605

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5 0
2 years ago
A gas has a volume of 10.0 liters at 373K and a pressure of 5.0atm, what volume will the gas occupy at STP?
zhannawk [14.2K]
Use ideal gas law PV=nRT
Convert 5.00 atm to kPa since units must be relative to gas constant (r).
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Solve for n (moles) to get approximately 1.634 mol. Now use dimensional analysis (1.634mol/1)(22.4L/1mol) = 36.6L
4 0
4 years ago
What is it with the name Sara these days!? XD
Komok [63]

66 mph

Explanation:

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The average speed of Sara's mum is 66mph

Learn more:

Average speed brainly.com/question/8893949

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7 0
3 years ago
Which of the following best describe the particles present in a 2.0 M aqueous solution of Al(NO3)3?2 M Al3+(aq) and 18 M NO3-(aq
zvonat [6]

Answer:

The correct answer is: 2M Al3+(aq) and 6 M NO3-(aq)

Explanation:

Step 1: Data given

2.0 M Al(NO3)3

Step 2:

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For 1 mol of Al(NO3)3 we will have 1 mol of Al^3+ and 3 moles of NO3^-

We know that the molarity of Al(NO3)3 = 2.0 M, this means 2.0 mol/ L

The mol ratio Al(NO3)3 and Al^3+ is 1:1 so the molarity of Al^3+ is<u> 2.0 M</u>

The mol ratio Al(NO3)3 and NO3^- is 1:3 so the molarity of NO3^- is<u> 6.0M</u>

The correct answer is: 2M Al3+(aq) and 6 M NO3-(aq)

3 0
3 years ago
What kind of molecule is glucose
Scrat [10]
Organic molecule. In particular,  a carbohydrate.
6 0
3 years ago
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