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mamaluj [8]
4 years ago
13

Describe how sediments are produced by weathering and erosion

Chemistry
2 answers:
TEA [102]4 years ago
5 0
Weathering is the physical or chemical process where rocks are broken down to form sediments.
 • Physical weathering does not change the rock’s composition.
 • Chemical weathering does change the rock’s composition
 • Erosion is the process where forces such as water, wind, ice, or gravity transport sediments to some remote location
boyakko [2]4 years ago
3 0

Answer:

Weathering is a process of water moving through rocks and making them erosionate, flowing and moving to a river and sediments in the bottom of the sea or a river

Explanation:

As you can see in the image below.

weathering <u>can be done by rain, wind or ice that moves through rocks.</u>

Erosion <em><u>is a process where rocks are melted down by the rain or wind that comes above and moving down hill to a river.</u></em>

Deposition <em><u>is the final process of the cycle where all the rocks,and soil were dragged  by water to the bottom of a river or sea.</u></em>

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A 500.0 mL sample of 0.18 MHClO4 is titrated with 0.27 MCsOH. Determine the pH of the solution after the addition of 250.0 mL of
NNADVOKAT [17]

Answer:

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Explanation:

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3 years ago
Write insoluble or soluble solution for the following mixtores<br>1<br>2<br>3<br>4<br>5<br>​
dimaraw [331]

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6 0
3 years ago
The radioisotope phosphorus-32 is used in tracers for measuring phosphorus uptake by plants. The half-life of phosphorus-32 is 1
Harman [31]

Answer:

54 days

Explanation:

We have to use the formula;

0.693/t1/2 =2.303/t log Ao/A

Where;

t1/2= half-life of phosphorus-32= 14.3 days

t= time taken for the activity to fall to 7.34% of its original value

Ao=initial activity of phosphorus-32

A= activity of phosphorus-32 after a time t

Note that;

A=0.0734Ao (the activity of the sample decreased to 7.34% of the activity of the original sample)

Substituting values;

0.693/14.3 = 2.303/t log Ao/0.0734Ao

0.693/14.3 = 2.303/t log 1/0.0734

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3 0
3 years ago
Can someone help me with this please
never [62]

Answer: B. 1:2

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The formula of the compound formed is BeCl2.

3 0
4 years ago
20.352 mL of chlorine under a pressure of 680. mm Hg are
Lunna [17]

Answer:

0.01144L or 1.144x10^-2L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 20.352 mL

P1 (initial pressure) = 680mmHg

P2 (final pressure) = 1210mmHg

V2 (final volume) =.?

Using the Boyle's law equation P1V1 = P2V2, the volume of the container can be obtained as follow:

P1V1 = P2V2

680 x 20.352 = 1210 x V2

Divide both side by 1210

V2 = (680 x 20.352)/1210

V2 = 11.44mL

Now we need to convert 11.44mL to L in order to obtain the desired result. This is illustrated below:

1000mL = 1 L

11.44mL = 11.44/1000 = 0.01144L

Therefore the volume of the container is 0.01144L or 1.144x10^-2L

7 0
3 years ago
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