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mamaluj [8]
3 years ago
13

Describe how sediments are produced by weathering and erosion

Chemistry
2 answers:
TEA [102]3 years ago
5 0
Weathering is the physical or chemical process where rocks are broken down to form sediments.
 • Physical weathering does not change the rock’s composition.
 • Chemical weathering does change the rock’s composition
 • Erosion is the process where forces such as water, wind, ice, or gravity transport sediments to some remote location
boyakko [2]3 years ago
3 0

Answer:

Weathering is a process of water moving through rocks and making them erosionate, flowing and moving to a river and sediments in the bottom of the sea or a river

Explanation:

As you can see in the image below.

weathering <u>can be done by rain, wind or ice that moves through rocks.</u>

Erosion <em><u>is a process where rocks are melted down by the rain or wind that comes above and moving down hill to a river.</u></em>

Deposition <em><u>is the final process of the cycle where all the rocks,and soil were dragged  by water to the bottom of a river or sea.</u></em>

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Which group of factors are most important in determining the composition of ocean water? a.)temperature, salinity, and density b
Elis [28]

Temperature, salinity, and density are the group of factors are most important in determining the composition of ocean water.

a.)temperature, salinity, and density

<u>Explanation:</u>

The three fundamental factors that help in determining the composition of ocean water are temperature, salinity, and density. Temperature, saltiness, salinity, and density influence the thickness of seawater.

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8 0
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17) A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with what volume? HI
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Answer: A 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

Explanation:

Given: M_{1} = 0.20 M,      V_{1} = 15.0 mL

M_{2} = 0.10 M,            V_{2} = ?

Formula used is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula s follows.

M_{1}V_{1} = M_{2}V_{2}\\0.20 M ]times 15.0 mL = 0.10 M ]times V_{2}\\V_{2} = 30 mL

Thus, we can conclude that a 0.20 M solution of HCl with a volume of 15.0 mL is exactly neutralized by the 0.10 M solution of NaOH with 3 mL volume.

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2 years ago
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