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mamaluj [8]
3 years ago
13

Describe how sediments are produced by weathering and erosion

Chemistry
2 answers:
TEA [102]3 years ago
5 0
Weathering is the physical or chemical process where rocks are broken down to form sediments.
 • Physical weathering does not change the rock’s composition.
 • Chemical weathering does change the rock’s composition
 • Erosion is the process where forces such as water, wind, ice, or gravity transport sediments to some remote location
boyakko [2]3 years ago
3 0

Answer:

Weathering is a process of water moving through rocks and making them erosionate, flowing and moving to a river and sediments in the bottom of the sea or a river

Explanation:

As you can see in the image below.

weathering <u>can be done by rain, wind or ice that moves through rocks.</u>

Erosion <em><u>is a process where rocks are melted down by the rain or wind that comes above and moving down hill to a river.</u></em>

Deposition <em><u>is the final process of the cycle where all the rocks,and soil were dragged  by water to the bottom of a river or sea.</u></em>

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A strontium hydroxide solution is prepared by dissolving 10.60 gg of Sr(OH)2Sr(OH)2 in water to make 47.00 mLmL of solution.What
NeTakaya

Answer:

Approximately 1.854\; \rm mol\cdot L^{-1}.

Explanation:

Note that both figures in the question come with four significant figures. Therefore, the answer should also be rounded to four significant figures. Intermediate results should have more significant figures than that.

<h3>Formula mass of strontium hydroxide</h3>

Look up the relative atomic mass of \rm Sr, \rm O, and \rm H on a modern periodic table. Keep at least four significant figures in each of these atomic mass data.

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Calculate the formula mass of \rm Sr(OH)_2:

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<h3>Number of moles of strontium hydroxide in the solution</h3>

M\left(\rm Sr(OH)_2\right) =121.634\; \rm g \cdot mol^{-1} means that each mole of \rm Sr(OH)_2 formula units have a mass of 121.634\; \rm g.

The question states that there are 10.60\; \rm g of \rm Sr(OH)_2 in this solution.

How many moles of \rm Sr(OH)_2 formula units would that be?

\begin{aligned}n\left(\rm Sr(OH)_2\right) &= \frac{m\left(\rm Sr(OH)_2\right)}{M\left(\rm Sr(OH)_2\right)}\\ &= \frac{10.60\; \rm g}{121.634\; \rm g \cdot mol^{-1}} \approx 8.71467\times 10^{-2}\; \rm mol\end{aligned}.

<h3>Molarity of this strontium hydroxide solution</h3>

There are 8.71467\times 10^{-2}\; \rm mol of \rm Sr(OH)_2 formula units in this 47\; \rm mL solution. Convert the unit of volume to liter:

V = 47\; \rm mL = 0.047\; \rm L.

The molarity of a solution measures its molar concentration. For this solution:

\begin{aligned}c\left(\rm Sr(OH)_2\right) &= \frac{n\left(\rm Sr(OH)_2\right)}{V}\\ &= \frac{8.71467\times 10^{-2}\; \rm mol}{0.047\; \rm L} \approx 1.854\; \rm mol \cdot L^{-1}\end{aligned}.

(Rounded to four significant figures.)

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Explanation:

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