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san4es73 [151]
3 years ago
10

Consider a process in which a carbon-based fuel is combusted in the presence of 70% excess oxygen (assume that all of the oxygen

present come from an air feel stream). Based on the information given above, which of the following statements are true? Select all that apply.
a. Exactly 70% of the oxygen presence in the process is not consumed.

b. 70% of the fuel in the process undergoes complete combustion.

c. At least 41% of the oxygen present in the grocers is not consumed

d. There is 70% more air present in the process that would be necessary for the complete combustion of all the fuel

e. There is 70% more oxygen present in the process that would be necessary for the complete combustion of all of the fuel
Engineering
1 answer:
yuradex [85]3 years ago
7 0

Answer:

<u>Option-(A):</u>

  • When a carbon-based fuel is burned(combustion) or we can say burned in the presence of 70% excess oxygen (assuming that all of the oxygen present come from an air feel stream), we can say that there is 70% more oxygen present in the process that would be necessary for the complete combustion of all of the fuel.
  • Oxygen,O₂ is the precursor for the process of combustion as there is the requirement of an optimum level of oxygen for the burning up of the materials.While, there is about enough level of oxygen is present inside the free air or we can say inside the atmosphere for the purpose of combustion or burning of the fuel or consumption of the resources present in the environment.

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3 years ago
Water flows through a pipe at an average temperature of T[infinity] = 70°C. The inner and outer radii of the pipe are r1 = 6 cm
Paul [167]

Answer:

The differential equation and the boundary conditions are;

A) -kdT(r1)/dr = h[T∞ - T(r1)]

B) -kdT(r2)/dr = q'_s = 734.56 W/m²

Explanation:

We are given;

T∞ = 70°C.

Inner radii pipe; r1 = 6cm = 0.06 m

Outer radii of pipe;r2 = 6.5cm=0.065 m

Electrical heat power; Q'_s = 300 W

Since power is 300 W per metre length, then; L = 1 m

Now, to the heat flux at the surface of the wire is given by the formula;

q'_s = Q'_s/A

Where A is area = 2πrL

We'll use r2 = 0.065 m

A = 2π(0.065) × 1 = 0.13π

Thus;

q'_s = 300/0.13π

q'_s = 734.56 W/m²

The differential equation and the boundary conditions are;

A) -kdT(r1)/dr = h[T∞ - T(r1)]

B) -kdT(r2)/dr = q'_s = 734.56 W/m²

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2 years ago
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The drag coefficient of a car at the design conditions of 1 atm, 25°C, and 90 km/h is to be determined experimentally in a large
SIZIF [17.4K]

Answer: 0.288

Explanation:

Given

Pressure of the car, P = 1 atm

Temperature of the car, T = 25° C

Speed of the car, v = 90 km/h = 90*1000/3600 = 25 m/s

Height of the car, h = 1.25 m

Width of the car, b = 1.65 m

Force acting on the far, F = 220 N

Drag coefficient, C(d) = ?

Using our table A-9, we can trace that the density of air ρ, at the given temperature and pressure of 25 °C and 1 atm, is 1.184 kg/m³

Area = h *b

Area = 1.25 * 1.65

Area = 2.0625 m²

Now we solve for the drag coefficient using the formula

C(d) = F / (1/2 * ρ * A * v²)

C(d) = 220 / (0.5 * 1.184 * 2.0625 * 25²)

C(d) = 220 / (1.221 * 625)

C(d) = 220 / 763.125

C(d) = 0.288

Therefore, the drag coefficient is 0.288

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