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liq [111]
3 years ago
10

Explain how you would solve for total resistance in a parallel circuit versus a series circuit. How would you apply and solve fo

r Kirchhoff’s current law in a parallel circuit, assuming you know the values of each resistor?
Engineering
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

No, series parallel, as it implies has components of the circuit configured in both series and parallel. This is typically done to achieve a desired resistance in the circuit. A parallel circuit is a circuit that only has the components hooked in parallel, which would result in a lower total resistance in the circuit than if the components were hooked up in a series parallel configuration.

Explanation:

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Select a research proposal topic that relates to electrical and electronics engineering and write a proposal report taking into
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3 years ago
The enforcement of OSHA standards is provided by federal and state
Gnoma [55]

Answer:

Explanation:

Enforcing OSHA, Occupational Safety and Health Administration, standards is not a job for electricians, lawmakers or tax collectors. The right answer is safety inspectors.

3 0
2 years ago
Drag each tile to the correct box.
Trava [24]

Answer:

Bluray

DVD

CD

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6 0
3 years ago
The role of civil and structural engineer is to produce buildings for
Alinara [238K]
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3 0
3 years ago
Determine the design moment strength for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compressio
SVETLANKA909090 [29]

This question is incomplete, the complete question is;

Determine the design moment strength (ϕMn) for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compression flange is provided at the ends only (i.e., Lb = 18 ft). Report the result in kip-ft.

Use Fy=50 ksi and assume Cb=1.0 (if needed).

Answer: the design moment strength for the W21x73 steel beam is 566.25 f-ft

Explanation:

Given that;

section  W 21 x 73 steel beam;

now from the steel table table for this section;

Zx = Sx = 151 in³

also given that; fy = 50 ksi and Cb = 1.0

QMn = 0.9 × Fy × Zx

so we substitute

QMn = 0.9 × 50 × 151

QMn = 6795 k-inch

we know that;

12inch equals 1 foot

so

QMn = 6795 k-inch / 12

QMn = 566.25 f-ft

Therefore the design moment strength for the W21x73 steel beam is 566.25 f-ft

7 0
3 years ago
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