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liq [111]
3 years ago
10

Explain how you would solve for total resistance in a parallel circuit versus a series circuit. How would you apply and solve fo

r Kirchhoff’s current law in a parallel circuit, assuming you know the values of each resistor?
Engineering
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

No, series parallel, as it implies has components of the circuit configured in both series and parallel. This is typically done to achieve a desired resistance in the circuit. A parallel circuit is a circuit that only has the components hooked in parallel, which would result in a lower total resistance in the circuit than if the components were hooked up in a series parallel configuration.

Explanation:

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Re armature of a 4 pole DC generator is required to generate an emf of 520v on open circuit when revolving at a speed of 660rpm.
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Since the armature is wave wound, the magnetic flux per pole is 0.0274 Weber.

<u>Given the following data:</u>

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To find the magnetic flux per pole:

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E = \frac{\theta ZN}{60} × \frac{P}{A}

<u>Where:</u>

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  • N is the speed or armature rotation in r.p.m.
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First of all, we would determine the total number of armature conductors:

Z = 144 × 2 × 3

Z = 864

Substituting the given parameters into the formula, we have;

520 = \frac{\theta (864)(660)}{60} × \frac{4}{2}

520 = \theta (864)(11) × 2

520 = 19008 \theta \\\\\Theta = \frac{520}{19008}

<em>Magnetic flux </em><em>=</em><em> 0.0274 Weber.</em>

Therefore, the magnetic flux per pole is 0.0274 Weber.

Read more: brainly.com/question/15449812?referrer=searchResults

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