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const2013 [10]
3 years ago
15

A CD player rotates at a variable speed so that a laser can scan pits and lands on the disk’s bottom surface at a constant tange

ntial speed of 1.2 m/s. The disk has a moment of inertia of 1.2 x 10-4 kg m2and the music is first detected when the laser is located 15 mm from the disk’s center. Assuming the disk started from rest, find the work done by the motor during this start-up.
Physics
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

W = 0.384 J

Explanation:

Work and energy in the rotational movement are related

    W = ΔK = K_{f} - K₀

    W = ½ I w_{f}² - 1 /2 I w₀²

where W isthe work, I is the moment of inertia and w angular velocity

With the system part of the rest the initial angular speed is zero (w₀ = 0)

The angular and linear quantities are related

    v = w r

    w = v / r

Let's replace

    W = ½ I (v / r)²

Let's calculate

    W = ½  1.2 10⁻⁴ 1.2² / (1.5 10⁻²)²

    W = 0.384 J

    W = 38.4 J

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The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7
My name is Ann [436]

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

4 0
3 years ago
What is The common value for the speed of light in a vacuum
Talja [164]
The most common value for the speed of light is 3*10^8 meters/second.

A more accurate number is <span>299 792 458 m/second, but that number is hardly ever used.</span>
4 0
4 years ago
Why do polar compounds tend to have higher melting points than nonpolar compounds
I am Lyosha [343]

Answer:

The inter-molecular forces holding non-polar compounds together is low compare to that of polar compounds. Therefore, it will take less energy to break the bond for non-polar compounds and vice versa. That is why polar compounds have higher melting points than non-polar compounds.

Explanation:

5 0
3 years ago
What would cause soil horizons to become mixed?
AfilCa [17]

Answer:

The process of soil formation generally involves the downward movement of clay, water, and dissolved ions, and a common result of that is the development of chemically and texturally different layers known as soil horizons. The typically developed soil horizons, as illustrated in Figure 5.16, are: O — the layer of organic matter A — the layer of partially decayed organic matter mixed with mineral material E— the eluviated (leached) layer from which some of the clay and iron

Explanation:

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7 0
3 years ago
A certain reaction with an activation energy of 185 kJ/mol was run at 525 K and again at 545 K . What is the ratio of f at the h
Kazeer [188]

Answer: The ratio of f at the higher temperature to f at the lower temperature is 4.736

Explanation:

According to the Arrhenius equation,

f=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{f_2}{f_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

f_1 = rate constant at 525K

K_2 = rate constant at 545K

Ea = activation energy for the reaction = 185kJ/mol= 185000J/mol   (1kJ=1000J)

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 525 K

T_2 = final temperature = 545 K

Now put all the given values in this formula, we get

\log (\frac{f_2}{f_1})=\frac{185000J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{525K}-\frac{1}{545K}]

\log (\frac{f_2}{f_1})=0.6754

(\frac{f_2}{f_1})=4.736

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 4.736

8 0
3 years ago
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