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Sindrei [870]
3 years ago
8

Polarizing windows, filters, etc. are often used to reduce the amount of light that enters the lens of a camera or into a room o

r a car. A library atrium has an overhead skylight that lets in too much light during the day which heats up the interior of the library far too much. The building engineer installs new double paned polarizing sky lights to reduce the intensity. If sunlight, which is unpolarized, has an average intensity of 1250 W/m^2.
Required:
What angle should the polarizing axis of the second pane of the window make with the polarizing axis of the first pane of the window in order to reduce the intensity of the sunlight to 33% of the original value?
Physics
1 answer:
LekaFEV [45]3 years ago
7 0

Answer:

The answer is "35.6^{\circ}"

Explanation:

The sunlight level of the first panel:

I_1 = \frac{I_o}{2}

When the light of this intensity passes through the second window:

I_2 = I_1 \cos^2 \theta\\\\I_2 = \frac{I_o}{2} \cos^2 \theta

 \frac{I_2}{I_o} = 0.33 (33\%) \\\\

therefore,  

0.33 = \frac{1}{2} \cos^2 \theta\\\\\cos^2 \theta = 0.66\\\\\cos \theta = \sqrt{0.66} = 0.8124\\\\\theta = \cos^{-1}( 0.8124) = 35.6^{\circ}\\\\

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The property of matter that is responsible for electrical phenomena, existing in a positive or negative form.
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Determine the direction in which an electrical signal is carried in a typical multipolar neuron
choli [55]
The direction in which an electrical signal is carried in a typical multi-polar neuron is:
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Specialized projection of neurons are dendrites and axon. The central part of neuron is cell body. So, the electrical signal is carried in a direction that first dendrites carried the signal then it goes towards cell body and then to axon.
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3 years ago
PLEASE HELP!!! WOULD REALLY APPRECIATE!
Eva8 [605]

Answer:

a. slope=rise/run

rise=0.02

run=-2

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3 0
2 years ago
A toy car having mass m = 1.50 kg collides inelastically with a toy train of mass M = 3.60 kg. Before the collision, the toy tra
baherus [9]

Answer:

  v_{f} = 3,126 m / s

Explanation:

In a crash exercise the moment is conserved, for this a system formed by all the bodies before and after the crash is defined, so that the forces involved have been internalized.

the car has a mass of m = 1.50 kg a speed of v1 = 4.758 m / s and the mass of the train is M = 3.60 kg and its speed v2 = 2.45 m / s

Before the crash

    p₀ = m v₁₀ + M v₂₀

After the inelastic shock

    p_{f}= m v_{1f} + M v_{2f}

    p₀ =  p_{f}

    m v₀ + M v₂₀ = m v_{1f}  + M v_{2f}

We cleared the end of the train

     M v_{2f} = m (v₁₀ - v1f) + M v₂₀

Let's calculate

     3.60 v2f = 1.50 (2.15-4.75) + 3.60 2.45

     v_{2f}  = (-3.9 + 8.82) /3.60

      v_{2f}  = 1.36 m / s

As we can see, this speed is lower than the speed of the car, so the two bodies are joined

set speed must be

      m v₁₀ + M v₂₀ = (m + M) v_{f}

      v_{f}  = (m v₁₀ + M v₂₀) / (m + M)

      v_{f}  = (1.50 4.75 + 3.60 2.45) /(1.50 + 3.60)

      v_{f} = 3,126 m / s

4 0
3 years ago
A thin partition divides a thermally insulated vessel into a lower compartment of volume V and an upper compartment of volume 2V
Anni [7]

Answer:

1.89mol

Explanation:

The entropy change during free expansion is express as

S_{f}-S_{i}=nRln(\frac{V_{F}}{V_{I}})\\

Where S is the entropy of the system,

            n is the amount of mole

             R is the gas constant = 8.314 and

           V is the volume occupied at the initial and final stage

since the process is n adiabatic free expansion, the entropy of the system is constant. Hence we can re-write the equation as

S=nRln(\frac{V_{F}}{V_{I}})\\

where the  V_{i}=v\\ and V_{f}=2v+v=3v\\

S=17.28J/k\\ and

R=8.314\\

Now if we substitute in values we arrive at

17.28=(8.314)n*ln(\frac{3v}{v} )\\17.28=(8.314)n*ln(3 )\\17.28=(8.314)n*1.0986\\n=\frac{17.28}{8.314*1.0989}\\n=1.89 mole\\

6 0
3 years ago
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