Answer:
(a) The equilibrium partial pressure of BrCl (g) will be greater than 2.00 atm.
Explanation:
Q is the coefficient of the reaction and is calculated the same of the way of the equilibrium constant, but using the concentrations or partial pressures in any moment of the reaction, so, for the reaction given:
Q = (pBrCl)²/(pBr₂*pCl₂)
Q = 2²/(1x1)
Q = 4
As Q < Kp, the reaction didn't reach the equilibrium, and the value must increase. As we can notice by the equation, Q is directly proportional to the partial pressure of BrCl, so it must increase, and be greater than 2.00 atm in the equilibrium.
The partial pressures of Br₂ and Cl₂ must decrease, so they will be smaller than 1.00 atm. And the total pressure must not change because of the stoichiometry of the reaction: there are 2 moles of the gas reactants for 2 moles of the gas products.
Because is a reversible reaction, it will not go to completion, it will reach an equilibrium, and as discussed above, the partial pressures will change.
Answer:
x is CO2
y is H2O
Explanation:
An organic compound that contains carbon and hydrogen is called a hydrocarbon.
When a hydrocarbon is burnt in air (combustion) only two products are obtained; carbon dioxide and water. The carbon dioxide comes from the carbon component of the molecule while the water comes from the hydrogen component of the molecule.
Therefore, for a hydrocarbon CxHy we obtain; xCO2 and (x + 1)H2O as products.
Answer:
.25
Explanation:
H+=10^-pH
- Hope that helps! Please let me know if you need further explanation.
