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Westkost [7]
3 years ago
12

1. What is the oxidizing agent in the following reaction? CH4 + 2O2 --> CO2 + H2O

Chemistry
2 answers:
Lena [83]3 years ago
8 0
2O2 IS THE OXIDIZING AGENT BECAUSE IT GIVES ALL OTHER ELEMENT OXYGEN
WARRIOR [948]3 years ago
7 0

Answer:

Oxygen gas (O₂)

Explanation:

Oxidizing agent is one which its self gets reduced and oxidizes the other.

Oxidation is the process where the oxidation number of substance increases while in reduction the oxidation number decreases.

The oxidation number of hydrogen in both methane and water is "+1"

Oxidation number of carbon in methane is "-4"

While its oxidation number in carbondioxide is "+4"

Thus carbon is undergoing oxidation.

While the change in oxidation number of oxygen from O₂ to CO₂ is "0" to -2

Hence it is undergoing reduction and oxidizing carbon.

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3 0
3 years ago
2H2 + O2 -&gt; 2H20
irina [24]

Answer:

                    144.08 g of H₂O

Explanation:

                     The balance chemical equation for the synthesis of water is as follow;

                                           2 H₂ + O₂ → 2 H₂O

Step 1: <u>Find out moles of H₂O produced as;</u>

According to balance chemical equation,

                    1 mole of O₂ produced  =  2 moles of H₂O

So,

                 4 moles of O₂ will produce  =  X moles of H₂O

Solving for X,

                    X =  4 mol × 2 mol / 1 mol

                    X  =  8 moles of H₂O

Step 2: <u>Calculate Mass of H₂O as;</u>

                 Mass  =  Moles × M.Mass

                 Mass  =  8 mol × 18.01 g/mol

                 Mass  = 144.08 g of H₂O

6 0
3 years ago
Please help with this chemistry question, image attached.
Alexeev081 [22]

Answer:

a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O

b. The conversion factor that Jacob did, was wrong.

Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:

9.45 mol . 102 g / 1 mol = 963.9 g

Explanation:

Al₂O₃ → Aluminum oxide

We determine the molar mass:

Molar mass Al . 2 + Molar mass O . 3

27 g/mol . 2 + 16 g/mol . 3 = 102 g/mol

a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O

b. The conversion factor that Jacob did, was wrong.

Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:

9.45 mol . 102 g / 1 mol = 963.9 g

7 0
3 years ago
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