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2 years ago

Cho 700ml dung dịch NaOH 0.1M vào 100ml dung dịch AlCl3 0.2M. Tính khối lượng kết tủa sau phản ứng

Chemistry

1 answer:

Licemer1 [7]2 years ago

8 0

English ? i can’t understand

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chlorine reacts with fluorine to form flowing monofluoride write an equation for this reaction including the state symbols are t

vovangra [49]

Cl +F = Cl2F

Hope this helped

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2 years ago

If the solid copper starts off at the normal melting temperature of copper and the liquid copper is put into the mold at the cry

Agata [3.3K]

Heat of what? This is an unclear question.

3 0

2 years ago

Ethanol, C2H6O, is most often blended with gasoline - usually as a 10 percent mix - to create a fuel called gasohol. Ethanol is

ch4aika [34]

Answer:

4054 kcal of heat is released during complete combustion of 354 g of octane.

Explanation:

Heat of combustion of 1 mol of octane is $1.308\times 10^{3}$ kcal

Molar mass of octane = 114.23 g/mol

We know, no. of moles = (mass)/(molar mass)

So, $1.308\times 10^{3}$ kcal of heat is released during complete combustion of 114.23 g of octane.

So, amount of heat is released during complete combustion of 354 g of octane = $(\frac{1.308\times 10^{3}}{114.23})\times 354$ kcal = 4054 kcal

Hence 4054 kcal of heat is released during complete combustion of 354 g of octane.

5 0

2 years ago

When a 10 mL graduated cylinder is filled to the 10 mL mark, the mass of the water was measured to be 9.925 g. If the density of

Vlada [557]

Measured volume = 10 ml
mass = 9.925 g
density = 0.9975 g/ml
density = $\frac{mass}{volume}$
so actual volume = $\frac{mass}{density}$ = $\frac{9.925}{0.9975}$ = 9.95 mL
Percentage Error = $\frac{measured volume - Actual volume}{actual volume}$ x 100
= $\frac{10 - 9.95}{9.95}$ x 100 = 0.5 % error

5 0

3 years ago

How many grams of NaCl (molecular weight = 58 Da) would you have to dissolve in 50ml to make a 2M stock solution? Answer:

Lerok [7]

Answer:

5.8 g

Explanation:

Molecular weight in Daltons is equivalent to the molecular weight in grams per mole.

The amount of NaCl required is calculated as follows:

(2 mol/L)(50 mL)(1 L/1000 mL) = 0.1 mol

This amount is converted to grams using the molar mass (58 g/mol).

(0.1 mol)(58 g/mol) = 5.8 g

7 0

3 years ago