Answer:
P = 0.0644 atm
Explanation:
Given that,
The pressure of a sample of gas is measured as 49 torr.
We need to convert this temperature to atmosphere.
The relation between torr and atmosphere is as follow :
1 atm = 760 torr
1 torr = (1/760) atm
49 torr = (49/760) atm
= 0.0644 atm
Hence, the presssure of the sample of gas is equal to 0.0644 atm.
Answer:
The answer to your question is:
Explanation:
Data
mass = 4.33 kg
E = 41.7 J
v = ?
Formula
Ke = (1/2)mv²
Clear v from the equation
v = √2ke/m
Substitution
v = √2(41.7)/4.33
v = 19.26 m/s Result
Answer:
The answer is in the attachment
Explanation:
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