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3 years ago

9

A box of mass 10 kg is pulled from the hold of a ship with an acceleration of 1 m/s^2 by a vertical rope attached to it .find th

e tension in the rope.

1 answer:

wlad13 [49]3 years ago

5 0

F=ma
Mass times acceleration
We have g (10ms^_2) and a (1 given)
So total would be
10 kg times (10+1) =
110 N

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$\Delta t=(\frac{20}{g'}+\sqrt{\frac{400}{g'^2}+\frac{100}{g'} } )-(\frac{20}{g}+\sqrt{\frac{400}{g^2}+\frac{100}{g} } )$

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$t_f'=\sqrt{\frac{400}{g'^2}+\frac{100}{g'} }$

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$t_f=\sqrt{\frac{400}{g^2}+\frac{100}{g} }$

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Explanation:

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