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4 years ago

14

What is center of mass?

1 answer:

yuradex [85]4 years ago

3 0

“a point representing the mean position of the matter in a body or system.”

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The Brazilian rain forest is an area with significant biodiversity. As the rain forest is replaced with agricultural land, it is

valina [46]

B I think I’m not sure tho

4 0

3 years ago

Read 2 more answers

HELP! 10 PTS! Two objects of different mass have equal, non-zero kinetic energies. Which object has the greater momentum?

Juli2301 [7.4K]

The heavier one. The explanation for this is that <span>momentum is directly proportional to mass. The more mass there is, the more momentum.

This is as simply as I could explain it, hope I helped :) </span>

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4 years ago

In an intense battle, gunfire can so concentrated that bullets from opposite sides collide in midair. Suppose that a bullet (wit

Vesnalui [34]

Answer:

velocity

a). $v_{f}=235.2 (m/s)$

direction

b). $\beta =71.3$

kinetic energy

c). $E_{K}=225.97N$

Explanation:

Those kind of question have two typical questions inside to response the final velocity and the direction finding the angle and finally the kinetic energy so each the information you need can find there so

a).

$m_{b}*v_{b}+m_{t}*v_{t}=(m_{b}+m_{t})*v_{f}$

solve to vf

$v_{fx}=\frac{m_{b}*v_{b}*cos(21.3)+m_{t}*v_{t}*cos(15.4)}{m_{b}+m_{t}}=\frac{5.12x10^{-3}kg*208(m/s)0.931+3.05x10^{-3}kg*228(m/s)*0.964}{(5.12x10^{-3}+3.05x10^{-3}kg)}$

$v_{fx}=222.94(m/s)$

$v_{fy}=\frac{m_{b}*v_{b}*sin(21.3)+m_{t}*v_{t}*sin(15.4)}{m_{b}+m_{t}}=\frac{5.12x10^{-3}kg*208(m/s)0.363+3.05x10^{-3}kg*228(m/s)*0.265}{(5.12x10^{-3}+3.05x10^{-3}kg)}$

$v_{fy}=75.21(m/s)$

$V_{f}=\sqrt{V_{fx}^2+V_{fy}}=\sqrt{222.94^2+75.21^2}$

$V_{f}=235.28\frac{m}{s}$

b).

$Tan(\beta)=\frac{v_{fx}}{v_{fy}}$

solve to β

$\beta =tan^-1*(\frac{222.94}{75.4})$

$\beta=tan^{-1}*2.956$

$\beta =71.3$

c).

Final kinetic energy

$E_{k}=\frac{1}{2}m_{t}*V_{f}^2$

$E_{k}=\frac{1}{2}(5.12x10^{-3}+3.05x10^{-3})kg*(235.2m/s)^2$

$E_{K}=225.97N$

6 0

4 years ago

Determination of Thermal Conductivity. In determining the thermal conductivity of an insulating material, the temperatures were

Goshia [24]

Answer:

k=0.0577w/mk

k=0.03338BTU/h-ft-ºF

Explanation:

First we use the equation for heat transfer by conduction and solve for K

Q=KA(T2-T1)/x

Where

q=heat

A=area

T=temperature

K=conductivity

x=thickness

solving for k

k=Qx/A(T2-T1)

Q/A=Heat flux=q

k=qx/(T2-T1)

k=35.1*0.025/(318.4-303.2)

K=0.0577w/mk

remember that 1 btu / hftk equals 1,729 w / mk

K=0.0577/1.729=0.03338BTU/h-ft-ºF

3 0

4 years ago

What are the dark spots and light areas on the moon called

Tems11 [23]

The dark spots on the moon are the craters and there light spots are made up of the moon dust technically called regolith

5 0

4 years ago