The percentage of light gets through three successive polarized filters is 24.9 %
From the question,
Given that,
Angle of transmission axis = 32.8°
The intensity of light emerging from the first polarizer is determined by the equation
I₁ = I₀ / 2
where I₀ ⇒ intensity of unpolarized light
The light emerging from the second polarizer can be mathematically represented by,
I₂ = I₁ x cos²θ
Substituting the values,
I₂ =( I₀/2) x cos²θ
= (I₀/2) x cos² (32.8 )
= (I₀/2) x 0.706
= (0.706 / 2 ) x I₀
The light emerging from the third polarizer is represented as,
I₃ = I₂ x cos²θ
Substituting the values in the above equation,
I₃ = ( 0.706 / 2 ) I₀ x cos² (32.8)
= (0.706 / 2 ) I₀ x 0.706
= 0.249 I₀
The percentage of intensity of light that gwts through with respect to the intensity of unpolarized light is given by the equation,
(I₃ / I₀) x 100
Substituting the values
[(0.249 x I₀) / I₀ ] x 100 = 24.9 %
Hence the percentage of light gets through is 24.9%
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Displacement from the center line for minimum intensity is 1.35 mm , width of the slit is 0.75 so Wavelength of the light is 506.25.
<h3>How to find Wavelength of the light?</h3>
When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity = 1.35 mm
λ = wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
To learn more about Wavelength of the light refer to:
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<h3>
Answer: D) 30</h3>
Angle of incidence always equals angle of reflection. Think of a tennis ball being hit into a wall. The ball will bounce off at the same angle that it approached with. The angles mentioned are formed through the line called the "normal", which is the line perpendicular to the surface.
Answer:
You would need to type the numbers in the question or you could have added a picture but you didn't so there is no way to answer this question. Have a nice day!
