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posledela
3 years ago
6

A 1.0 kg ball falls from rest a distance of 15m. what was its change in potential energy

Physics
1 answer:
expeople1 [14]3 years ago
8 0

Answer:

112.5 J

Explanation:

I calculated it by K/G BY M/S TO POTENTIAL ENERGY.

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Sarah's group designed this oven and eventually melted the
torisob [31]

Answer:

b

Explanation:

because i don't he asking me

5 0
3 years ago
The earth exerts the necessary centripetal force on an orbiting satellite to keep it moving in a circle at constant speed. Which
jenyasd209 [6]

Answer:

E) The centripetal force is always perpendicular to the velocity.

Explanation:

Due to gravity and inertia, the satellite follows a uniform circular motion. In this movement, the velocity is always tangent to the orbit and the centripetal force is directed towards the center. Therefore, there is no net acceleration in the same direction of velocity, which implies that it remains constant.

8 0
3 years ago
An ideal monatomic gas at temperature T is held in a container. If the gas is compressed isothermally, that is at constant tempe
OlgaM077 [116]

Answer:

a) 0 J

b) W = nRTln(Vf/Vi)

c) ΔQ = nRTln(Vf/Vi)

d) ΔQ = W

Explanation:

a) To find the change in the internal energy you use the 1st law of thermodynamics:

\Delta U=\Delta Q-W

Q: heat transfer

W: work done by the gas

The gas is compressed isothermally, then, there is no change in the internal energy and you have

ΔU = 0 J

b) The work is done by the gas, not over the gas.

The work is given by the following formula:

\\W=nRTln(\frac{V_f}{V_i})

n: moles

R: ideal gas constant

T: constant temperature

Vf: final volume

Vi: initial volume

Vf < Vi, then W < 0 and the work is done on the gas

c) The gas has been compressed. Thus, its temperature increases and heat has been transferred to the gas.

The amount of heat is equal to the work done W

d)

\Delta U = \Delta Q-W\\\\0=\Delta Q-W\\\\\Delta Q=W=nRTln(\frac{V_f}{V_i})

5 0
3 years ago
Can u plz help I'm failing and I have 2 weeks to get my grades up someone help me plz plz plz plz this is not a test ok it was h
Anastaziya [24]
1. B
2. A
3. B
4. C
5. heterogeneous
6. element
7. do
8. true
9. true
10. true
7 0
3 years ago
Read 2 more answers
A car accelerates at a constant rate from 0 to 50 mph in three fourths min. How far does the car travel during that​ time?
Helen [10]

Answer:

the car have travelled 0.31 mile during that​ time

Explanation:

Applying the Equation of motion;

s = 0.5(u+v)t

Where;

s = distance travelled

u = initial speed = 0 mph

v = Final speed = 50 mph

t = time taken = 3/4 min = 3/4 ÷ 60 hours = 1/80 hour

Substituting the given values into the equation;

s = 0.5(0+50)×(1/80)

s = 0.3125 miles

s ~= 0.31 mile

the car have travelled 0.31 mile during that​ time

8 0
3 years ago
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