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zalisa [80]
2 years ago
6

2. When heated above 500 ºC, potassium nitrate decomposes according to the equation below. 4KNO3 2K2O + 2N2 + 5O2A.If oxygen is

being formed at a rate of 0.30 M/s, what are the rates of formation of the other products? B.What is the rate at which the potassium nitrate is decomposed?
Chemistry
1 answer:
AysviL [449]2 years ago
3 0

Answer:

(a) The rate of formation of K2O is 0.12 M/s.

The rate of formation of N2 is also 0.12 M/s

(b) The rate of decomposition of KNO3 is 0.24 M/s

Explanation:

(a) From the equation of reaction, the mole ratio of K2O to O2 is 2:5.

Rate of formation of O2 is 0.3 M/s

Therefore, rate of formation of K2O = (2×0.3/5) = 0.12 M/s

Also from the equation of reaction, mole ratio of N2 to O2 is 2:5.

Rate of formation of N2 = (2×0.3/5) = 0.12 M/s

(b) From the equation of reaction, mole ratio of KNO3 to O2 is 4:5.

Therefore, rate of decomposition of KNO3 = (4×0.3/5) = 0.24 M/s

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Alexeev081 [22]

Answer: Theoretical yield is calculated based on the stoichiometry of the chemical equation. The actual yield is experimentally determined. The percent yield is determined by calculating the ratio of actual yield/theoretical yield.

Explanation:

5 0
2 years ago
I PLEASE HELP! How many liters of a 2.25 molar hydrobromic acid (HBr) solution would be needed to react completely with 100.0 gr
PtichkaEL [24]
Moles of calcium metal used = 100/40.1=2.5
Moles of HBr need to react = 5 moles 
As the molar ratio is 1 is to 2 among them 
so
Moles=molarity x volume
5=2.25 x volume
volume=2.22 litres of HBr required for this reaction
ANSWER IS 2.22 LITRES
8 0
2 years ago
Select the correct term to complete each sentence.
leva [86]

Answer: 1. halve

2. halve

3. double

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=\frac{hc}{\lambda}

E= energy

\lambda = wavelength of the wave

h = Planck's constant  

c = speed of light

Thus as wavelength and energy have inverse realation, when wavelength will halve , energy will double.

2. The between wavenumber and energy of the wave follows the equation:

E=h\times c\times \bar{\nu}

E= energy

\bar{\nu}\nubar = wavenumber of the wave

h = Planck's constant  

c = speed of light

Thus as wavenumber and energy have direct relation, when wavenumber will halve , energy will be halved.

3. The relationship between energy and frequency of the wave follows the equation:

E=h\times \nu

where

E = energy

h = Planck's constant  

\nu = frequency of the wave

Thus as frequency and energy have direct realation, when frequency will double , energy will double.

3 0
2 years ago
Air has a mass of 1.2g and a volume of 4,555ml. What is the density
coldgirl [10]

Answer:

<h2>Density = 0.00026 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density(\rho) =  \frac{mass}{volume}</h3>

From the question

mass of air = 1.2 g

volume = 4,555 mL

Substitute the values into the above formula and solve for the density

That's

<h3>Density =  \frac{1.2}{4555}</h3>

= 0.0002634

We have the final answer as

<h3>Density = 0.00026 g/mL</h3>

Hope this helps you

3 0
3 years ago
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Andrews [41]

Answer:

Explanation:

The oxidation state, sometimes referred to as oxidation number, describes the degree of oxidation (loss of electrons) of an atom in a chemical compound. Conceptually, the oxidation state, which may be positive, negative or zero, is the hypothetical charge that an atom would have if all bonds to atoms of different elements were 100% ionic, with no covalent component. This is never exactly true for real bonds.

The term oxidation was first used by Antoine Lavoisier to signify reaction of a substance with oxygen. Much later, it was realized that the substance, upon being oxidized, loses electrons, and the meaning was extended to include other reactions in which electrons are lost, regardless of whether oxygen was involved.

Helped?

Brainliest?

7 0
2 years ago
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