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Sav [38]
3 years ago
14

How many moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess?

Chemistry
2 answers:
SashulF [63]3 years ago
5 0

Answer:

2.57

Explanation:

Sindrei [870]3 years ago
3 0

Answer: The number of moles of NaCl produced will be, 3.61 moles.

Explanation : Given,

Mass of Na = 83.0 g

Molar mass of Na = 23 g/mol

First we have to calculate the moles of Na

\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}

\text{Moles of }Na=\frac{83.0g}{23g/mol}=3.61mol

Now we have to calculate the moles of NaCl

The balanced chemical equation is:

2Na+Cl_2\rightarrow 2NaCl

From the reaction, we conclude that

As, 2 mole of Na react to give 2 mole of NaCl

So, 3.61 mole of Na react to give 3.61 mole of NaCl

Therefore, the number of moles of NaCl produced will be, 3.61 moles.

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