<h3>
![\tt Kc=\dfrac{[CO_2]}{[C][O_2]}](https://tex.z-dn.net/?f=%5Ctt%20Kc%3D%5Cdfrac%7B%5BCO_2%5D%7D%7B%5BC%5D%5BO_2%5D%7D)
</h3><h3>Further explanation</h3>
Given
Reaction
C+02 = CO2
Required
The equilibrium constant
Solution
The equilibrium constant is the ratio of concentration or pressure between the product and the reactant with each reaction coefficient raised
The equilibrium constant is based on the concentration (Kc) in a reaction
pA + qB -----> mC + nD
![\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BKc%20~%20%3D%20~%20%5Cfrac%20%7B%5BC%5D%20%5E%20m%20%5BD%5D%20%5E%20n%7D%20%7B%5BA%5D%20%5E%20p%20%5BB%5D%20%5E%20q%7D%7D%7D%7D)
So for the reaction :
C+O₂ ⇔ CO₂
![\tt Kc=\dfrac{[CO_2]}{[C][O_2]}](https://tex.z-dn.net/?f=%5Ctt%20Kc%3D%5Cdfrac%7B%5BCO_2%5D%7D%7B%5BC%5D%5BO_2%5D%7D)
This is true, this isn't a question, it's a fact.
This is the balanced eq
N2 + 3H2 -> 2NH3
first you need to find mole of N2 by using
mol = mass ÷ molar mass.
mol N2= 20g ÷ (14.01×2)g/mol
=0.7138mol
then look at the coefficient between H2 and NH3.
it is N2:NH3
1:2
0.7138:0.7138×2
0.7138:1.4276 moles
moles of NH3 = 1.4276 moles
Answer:
Hello friends
Explanation:
<h3>For a given principal quantum number for or n, the corresponding angular quantum number or is equivalent to a range between 0 and( n-1)</h3>
<h3>This means that the angular quantum number for a principal quantum number of 2 is equivalent to.</h3>
<h3>1 = 0 - > (n - 1) = 0 - > (2 - 1) = 0 - > 1</h3>
<h3>Hope it's helpfully. </h3>
Answer:
Here's what I get
Explanation:
1. Sugar
(a) Dissolving in water
The white solid dissolves in water to give a colourless solution. There is no evidence that a new substance is being produced.
(b) Addition of sodium hydroxide
Adding the colourless solution of sodium hydroxide to the colourless sugar solution gives a colourless solution. There is no evidence that a new substance is being produced.
2. Magnesium sulfate
(a) Dissolving in water
The colourless crystals dissolve in water to give a colourless solution. There is no evidence that a new substance is being produced.
(b) Addition of sodium hydroxide
Adding the colourless solution of sodium hydroxide to the colourless solution of magnesium sulfate gives a white precipitate (see image). This is evidence that a new substance is being produced.