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3 years ago

9

A gas has a volume of 4 L at a temperature of -33°C. if the temperature is increased to 27°C in the pressure remains constant wh

at will be the new volume of the gas

1 answer:

vitfil [10]3 years ago

4 0

Answer:

5L

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

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Dichlorine heptoxide (C1 2 0 7) is a

Setler [38]

Answer:

Identify the "given" information and what the problem is asking you to "find."

Given : Cl2O7

Find: % Composition (% Cl and %O)

List other known quantities.

Mass of Cl in 1 mol Cl2O7 , 2 Cl : 2 x 35.45 g = 70.90 g

Mass of O in 1 mol Cl2O7 , 7 O: 7 x 16.00 g = 112.00 g

Molar mass of Cl2O7 = 182.90 g/mol

8 0

3 years ago

Consider the reaction of magnesium metal with hydrochloric acid to produce magnesium chloride and hydrogen gas. If 3.56 mol of m

pishuonlain [190]

<h3>Answer:</h3>

43.27 g Mg

<h3>Explanation:</h3>

The balanced equation for the reaction between magnesium metal and hydrochloric acid is;

Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)

From the equation;

1 mole of magnesium reacts with 2 moles of HCl

We are given;

3.56 moles of Mg and 3.56 moles of HCl

Using the mole ratio;

3.56 moles of Mg would react with 7.12 moles of HCl, and

3.56 moles of HCl would react with 1.78 moles of Mg

Therefore;

The amount of magnesium was in excess;

Moles of Mg left = 3.56 moles - 1.78 moles

= 1.78 moles

But; 1 mole of Mg = 24.305 g/mol

Therefore;

Mass of magnesium left = 1.78 moles × 24.305 g/mol

= 43.2629 g

= 43.27 g

Thus, the mass of magnesium that remained after the reaction is 43.27 g

4 0

3 years ago

Why do we balance chemical reaction

morpeh [17]

Hey there!

We balance chemical equations because of the law of conservation of mass.

The law of conservation of mass states that matter cannot be created or destroyed, so we must have the same amount of each element on each side of a chemical equation.

The products of a chemical reaction must be equal to the reactants to follow the law of conservation of mass.

Hope this helps!

3 0

3 years ago

Calculate the percentage of the void space out of the total volume occupied by 1 mole of water molecules. The density of water i

gtnhenbr [62]

Answer:

The percentage of the void space out of the total volume occupied is 93.11%

Explanation:

A mole of water contains 2 atoms of hydrogen and 1 atom of oxygen.

To calculate the volume of a mole of water, we calculate 2 times the volume of the hydrogen atom and 1 times the volume of the oxygen atom

Let's calculate this one after the other.

For the hydrogen, formula for the volume will be

$V_{hydrogen$ = 2 × 4/3 × π × $r_{H}^{3}$

where $r_{H}^{3}$ = 37 pm which is read as 37 picometer (1 picometer = 10^-12 m) = 37 × $10^{-12}$ meters

Volume of the hydrogen = 8/3 × (37 × 10^-12)^3 = 4.05 * 10^-31

we multiply this by the avogadro's number = 6.02 * 10^23

= 4.05 * 10^-31 * 6.02 * 10^23 = 2.6 * 10^-8 m^3

We do same for thr oxygen, but this time we do not multiply the volume of the oxygen by 2 as we have only one atom of oxygen

Volume of oxygen = 4/3 * π * (73 * 10^-12) ^3 * avogadro's number = 9.81 * 10^-7 m^3

adding both volumes together, we have 1.24 * 10^-6 m^3 or simply 1.24 ml ( 0.01 m = 1 ml)

Dividing the molar mass of one mole of water by its density, we can get the volume of 1 mole of water

= (18g/mol)/(1 g/ml) = 18 ml/mol

Now we proceed to calculate the volume of void = Total volume - volume of molecule = 18 - 1.24 = 16.76 ml

Now, the percentage of void = volume of void/total volume * 100%

= 16.76/18 * 100% = 93.11%

7 0

3 years ago

The double replacement reaction between calcium nitrate (Ca(NO3)2) and potassium oxide (K2O ) is shown below:

Llana [10]

Answer:

Mass = 2.355 g

Explanation:

Given data:

Mass of K₂O needed = ?

Mass of KNO₃ produced = 5.00 g

Solution:

Chemical equation:

K₂O + Ca(NO₃)₂ → CaO + 2KNO₃

Number of moles of KNO₃:

Number of moles = mass/molar mass

Number of moles = 5.00 g/ 101.1 g/mol

Number of moles = 0.05 mol

now we will compare the moles of KNO₃ and K₂O.

KNO₃ : K₂O

2 : 1

0.05 : 1/2×0.05 = 0.025 mol

Mass of potassium oxide needed in gram:

Mass = number of moles × molar mass

Mass = 0.025 mol × 94.2 g/mol

Mass = 2.355 g

8 0

3 years ago