Physical. you didn't burn it or create a chemical reaction
<u>Answer:</u> The molarity of Iron (III) chloride is 0.622 M.
<u>Explanation:</u>
Molarity is defined as the number of moles present in one liter of solution. The equation used to calculate molarity of the solution is:

Or,

We are given:
Mass of iron (III) chloride = 1.01 g
Molar mass of iron (III) chloride = 162.2 g/mol
Volume of the solution = 10 mL
Putting values in above equation, we get:

Hence, the molarity of Iron (III) chloride is 0.622 M.
Answer:
I think acetone has more because water is just H20
Answer:
C. An electron at this electrode has a higher potential energy than it has at a standard hydrogen electrode.
Explanation:
The standard hydrogen electrode (SHE) is used to measure the electrode potential of substances. The standard hydrogen electrode is arbitrarily assigned an electrode potential of zero. Recall that electrode potentials are always measured as reduction potentials in electrochemical systems.
For an electrode that has a negative electrode potential, electrons at this electrode have a higher potential energy compared to electrons at the standard hydrogen electrode. Electrons flow from this electrode to the hydrogen electrode.
On the other hand, a positive electrode potential implies that an electron at this electrode has a lower potential energy than it has at a standard hydrogen electrode. Hence electrons will flow from the standard hydrogen electrode to this electrode.
Answer:
Explanation:
Diethyl malonate is more acidic than monocarbonyl compounds (pKa=13) due to their alpha hydrogens being attached to two carbonyl groups. Thus, the <u>malonic ester is easily converted to its enolate ion by reaction with sodium ethoxide in ethanol</u>. The product of the alkylation of the malonic ester leaves a <u>hydrogen atom acid in an alpha position</u>, so the alkylation process can be repeated a second time to produce a dialkylated malonic ester.
In this case, when urea is treated with diethyl malonate in the presence of sodium ethoxide base,<u> the second alkylation step occurs intramolecularly</u> to generate a cyclic product, barbituric acid.