Ask question

Ask question

All categories

3 years ago

15

Preston adopted a cat from a rescue shelter. He needs to buy some cat litter, so he compares prices at different stores. He find

s the best deal at Fluffy Felines Pet Shop, which sells a 20-pound jug of cat litter for $8.60. How much does the cat litter cost per pound?

1 answer:

Sladkaya [172]3 years ago

8 0

Answer:

$0.43

Step-by-step explanation:

Preston adopted a cat from a rescue shelter

He needs to buy food for his new cat so he compared the price of cat litter at different stores

Preston gets the best deal at fluffy felines pet shop

They sell 20 pound jug litter for $8.60

Therefore the cost of the cat litter per pound can be calculated as follows

= 8.60/20

= 0.43

Hence the cost of the cat litter per pound is $0.43

You might be interested in

PLEASE HELP ASAP

maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

3 0

3 years ago

Geogre is building fence he builds fence at a constant rate of 2/3

SpyIntel [72]

Answer:

10

Step-by-step explanation:

4 0

3 years ago

Please help me with this

Ipatiy [6.2K]

Answer:

(-4,1) because if the x value repeats the relation is no longer a function

7 0

2 years ago

Read 2 more answers

Identify a and b in the binomial expression (2x3 + 3y2)7.

Shkiper50 [21]

$\text{Hey there!}$

$\text{Distribute the value of 7 in each of your terms}$

$\text{(2x}^3+\text{3y}^2)(7)$

$\text{2x}^3\times7=\text{14x}^3$

$\text{3y}^2\times7=\text{21y}^2$

$\text{We cannot combine like terms because they AREN'T any in this equation}$

$\boxed{\boxed{\bf{Answer:14x^3+21y^2}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{LoveYourselfFirst:)}$

8 0

3 years ago

Read 2 more answers

Use estimation to solve 2, 697/9

kotegsom [21]

300 is the best answer plse make me brainliest

5 0

3 years ago