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Alika [10]
4 years ago
12

How much does Nestle pay the local municipality for access to their spring water?

Physics
1 answer:
Lera25 [3.4K]4 years ago
5 0
Around 750 to 1,500.

      Hope I helped!
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A hiker leaves her camp and walks 3.5 km in a direction of 55° south of west to the lake. after a short rest at the lake, she hi
3241004551 [841]

Let's choose east as positive x-direction and south as positive y-direction. We can resolve the two displacement along these two axes:

- Displacement 1 (3.5 km, 55^{\circ} south of west

d_{1x}=-(3.5 km)( cos 55^{\circ})=-2.01 km

d_{1y}=(3.5 km)( sin 55^{\circ})=2.87 km

- Displacement 2 (2.7 km, 16^{\circ} east of south

d_{2x}=(2.7 km)( sin 16^{\circ})=0.74 km

d_{1y}=(2.7 km)( cos 16^{\circ})=2.60 km

So, the total components on the two directions are

d_x = -2.01 km+0.74 km=-1.27 km

d_y=2.87 km+2.60 km=5.47 km

And the magnitude of the hiker's resultant displacement is

d=\sqrt{(1.27 km)^2+(5.47 km)^2}=5.6 km

8 0
3 years ago
Read 2 more answers
Consider that 168.0 J of work is done on a system and 305.6 J of heat is extracted from the system. In the sense of the first la
Ilia_Sergeevich [38]

To solve this problem we must resort to the Work Theorem, internal energy and Heat transfer. Summarized in the first law of thermodynamics.

dQ = dU + dW

Where,

Q = Heat

U = Internal Energy

By reference system and nomenclature we know that the work done ON the system is taken negative and the heat extracted is also considered negative, therefore

W = -168J \righarrow  Work is done ON the system

Q = -305.6J \rightarrow Heat is extracted FROM the system

Therefore the value of the Work done on the system is -158.0J

3 0
3 years ago
A bowling ball of mass 5.8 kg moves in a
evablogger [386]

Answer:

Velocity of the ping pong ball must be = V2= 6,035.34m/s

Explanation:

M1= momentum of the bowling ball

m1 = mass of the bowling ball= 5.8kg

v1= velocity of the bowling ball= 1.59m/s

M2= momentum of the ping pong ball

m2= mass of the ping pong ball= 1.528 g/1000=  0.001528kg

v2= velocity of the ping pong ball

Momentum of the bowling ball= M1= m1v1= 5.8* 1.59= 9.222 kg-m/s

Momentum of the ping pong ball = M2= M1= m2v2

= 0.001528 *v2= 9.222

v2= 9.222/0.001528= 6,035.34 m/s

7 0
3 years ago
A 26.0 kg child plays on a swing having support ropes that are 2.40 m long. A friend pulls her back until the ropes are 45.0 ∘ f
Sloan [31]
A)Ep'=mgh=mgl(1-cosa).At the bottom of the swing Ep=0(reference level),so the potential energy as the child is just released is bigger than the potential energy at the bottom of the swing.;B)The speed of the child at the bottom of the swing-->v=√(2gh)=√[2gl(1-cosa)];C)I don't think that the tension does any work.
8 0
3 years ago
What is the term for substances that have several unpaired electrons and are strongly magnetic
Murljashka [212]

Answer:

Scientific definitions for ferromagnetic

The property of being strongly attracted to either pole of a magnet. Ferromagnetic materials, such as iron, contain unpaired electrons, each with a small magnetic field of its own, that align readily with each other in response to an external magnetic field.

Explanation:

8 0
3 years ago
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