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3 years ago

On a sunny day, your clothing becomes hot because

Physics

1 answer:

Brilliant_brown [7]3 years ago

4 0

Answer:

It is A.Heat is transmitted and light is reflected.

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A certain car battery with a 12.0 V emf has an initial charge of 131 A · h. Assuming that the potential across the terminals sta

irga5000 [103]

Answer:

The battery can supply 130 W for 11.75 h

Explanation:

In order to discover the time in wich the battery can supply this energy we need to find how much current is being drawn from it, we do that by using the equation for real power that is P = V*I, since we have V and P we can solve for I as seen bellow:

I = P/V = 130/12 = 10.834 A

We can use this value to find how many hours the power can supply said current. We do that by dividing the current capacity of the battery by the current drawn:

t = 141/12 = 11.75 h

7 0

2 years ago

If a light is moved twice (2x) as far from a surface, the area the light covers is ___ as big.

Ksenya-84 [330]

Answer:

twice

Explanation:

From magnification = height of image / height of object

Distance of image/ distance of object = magnification

If the distance and height of the object represents the initial light distance and the exposed surface respectively.

And similarly the distance and height of the image represents the final light distance and the exposed surface respectively.

Hence the new image exposure would be twice as large.

If we use the formula our point of investigation is Height of image,

H2= D2/D1× H1

H2 = 2D2/D1 × H1

H2 = 2H1

6 0

2 years ago

SELECT ALL THAT APPLY!! Which of the following are considered SIGNS that a chemical reaction occurred?

MAXImum [283]

Answer:

Formation of a Precipitate

Unexpected Color Change

Formation of a Gas

Explanation:

8 0

2 years ago

Given that the acceleration of gravity at the surface of Mars is0.38 of what it is one Earth, and that Mars' radius is 3400 km,d

evablogger [386]

Answer:

$1.156\times 10^{24}\ kg$

Explanation:

Given:

Gravity of Mars = 0.38 times the gravity at Earth

Gravity of Earth is, $g_{Earth}=9.8\ m/s^2$

Radius of Mars (R) = 3400 km

Mass of mars (M) = ?

We know that, the acceleration due to gravity of a planet of mass 'M' and radius 'R' is given as:

$g=\dfrac{GM}{R^2}$

Now, as per question:

$g_{Mars}=0.68g_{Earth}$

Plug in 9.8 for $g_{Earth}$ and solve for $g_{Mars}$ . This gives,

$g_{Mars}=0.68\times 9.8=6.67\ m/s^2$

Now, plug in this value in the above equation and solve for 'M'. This gives,

$6.67=\frac{6.67\times 10^{-11}M}{(3400\times 10^3)^2}\\\\1.156\times 10^{13}=10^{-11}M\\\\M=\frac{1.156\times 10^{13}}{10^{-11}}\\\\M=1.156\times 10^{24}\ kg$

Therefore, the mass of Mars is $1.156\times 10^{24}\ kg$ .

4 0

2 years ago

Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a –80-nC charge at x = –4 m on

olchik [2.2K]

Answer:

The answer is + 4.8V

Explanation:

The electric potential is

V = k ∑ $q_{i} / r_{i}$

We apply this expression to our case with three charges

V = k (q₁ / r₁ + q₂ / r₂ + q₃ / r₃)

The distance is

R = √((x-x₀)² + (y-y₀)²+ (z-z₀)²)

Let's find the distances

q₁ = 50 10⁻⁹ C

r₁ = √ ((8-0)² + (0-6)²)

r₁ = 10m

q₂ = -80 10⁻⁹ C

r₂ = √ ((8 + 4)²

r₂ = 12m

q₃ = 70 10⁻⁹ C

r₃ = √ ((8-0)²+ (0 + 6)²)

r₃ = 10 m

We calculate the potential

V = 8.99 10⁸ 10⁻⁹ (50/10 -80/12 +70/10)

V = 4.795 V

The answer is + 4.8V

5 0

3 years ago

Read 2 more answers