By definition we have that the linear moment is
p = m * v
Where
m = mass
v = speed.
Clearing the mass we have
m = p / v
Substituting the values
m= (13,300 kgm/s)/(14 m/s)=950Kg
the mass of the car is 950 Kg
Refer to the diagram shown below.
The net force acting on the vehicle is
F - R = 1060 -1010 = 50 N
The distance traveled is 21 m. Because the force is constant, the work done is
W = (50 N)*(21 m) = 1050 J
Assume that energy is not dissipated by air resistance or otherwise.
Conservation of energy requires that W = KE, where KE is the kinetic energy of the vehicle.
The KE is
KE = (1/2)*(2000 kg)*(v m/s)² = 1000v² J
Equate KE and W to obtain
1000v² = 1050
v² = 1.05
v = 1.025 m/s
Answer: 1.025 m/s
Power = (work) / (time)
Work = (power) x (time)
= (4 watts) x (8 hours)
1 "watt" = 1 joule/sec .
Work = (4 joule/sec) x (8 hours) x (3,600 sec/hr)
= (4 x 8 x 3,600) joules = 1,024 joules .
==================================
Another way:
4 watts = 0.004 kilowatt
Work = energy = (power) x (time)
= (0.004 kw) x (8 hrs) = 0.032 kilowatt-hour .
We have first velocity equals 8 m/s and the kinetic energy is 480 J
The order is the mass of the object
We have this formula K= mv2/2 isolating the mass we have m=k/v2
Now we will have m=480/8×8 > m= 480/64 m= 7.5kg now we deternimed the mass it's 7.5 kg