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3 years ago

Solve equation 2x-3=21+10x

Mathematics

2 answers:

eimsori [14]3 years ago

8 0

Answer:

x=-3

Step-by-step explanation:

First, Isolate and combine the x variables.

So, subtract 10x on both sides and get: -8x -3=21

Add 3 on both sides.

-8x=24

Divide 24 by -8

you should get: x=-3

<h2>PLEASE MARK BRAINLIEST!!! :)</h2>

levacccp [35]3 years ago

6 0

Answer:

x = -3

Step-by-step explanation:

2x-3=21+10x

Subtract 2x from each side

2x-2x-3=21+10x-2x

-3 = 21 +8x

Subtract 21 from each side

-3-21 = 21-21 +8x

-24 = 8x

Divide each side by 8

-24/8 = 8x/8

-3 =x

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3 years ago

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OLEGan [10]

Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

Consider h(x)=x^2+8+15. identify its vertex and y-intercept.

OleMash [197]

Answer:

Vertex: (-4, -1)

Y-intercept: (0, 15)

Step-by-step explanation:

Given the quaratic function, h(x) = x² + 8x + 15:

In order to determine the vertex of the given function, we can use the formula, $[x = \frac{-b}{2a}, h(\frac{-b}{2a})]$ .

<h3>Use the equation: $[x = \frac{-b}{2a}, h(\frac{-b}{2a})]$ </h3>

In the quadratic function, h(x) = x² + 8x + 15, where:

a = 1, b = 8, and c = 15:

Substitute the given values for <em>a</em> and <em>b</em> into the equation to solve for the x-coordinate of the vertex.

$x = \frac{-b}{2a}$

$x = \frac{-8}{2(1)}$

x = -4

Subsitute the value of the x-coordinate into the given function to solve for the <u>y-coordinate of the vertex</u>:

h(x) = x² + 8x + 15

h(-4) = (-4)² + 8(-4) + 15

h(-4) = 16 - 32 + 15

h(-4) = -1

Therefore, the vertex of the given function is (-4, -1).

<h3>Solve for the Y-intercept:</h3>

The <u>y-intercept</u> is the point on the graph where it crosse the y-axis. In order to find the y-intercept of the function, set x = 0, and solve for the y-intercept:

h(x) = x² + 8x + 15

h(0) = (0)² + 8(0) + 15

h(0) = 0 + 0 + 15

h(0) = 15

Therefore, the y-intercept of the quadratic function is (0, 15).

5 0

3 years ago