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3 years ago

I spent 3/4 of my money and then I spent 1/5 of what was left.

Mathematics

1 answer:

Kazeer [188]3 years ago

4 0

(3/4)+(1/5(1/4)

As my thinking, this is the answer...

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4(b+24)=(12b+8) pls help

vfiekz [6]

Answer:

b=11

Step-by-step explanation:

4(b+24)=(12b+8)

4b+96=12b+8

-4. -4

96=8b+8

-8. -8

88=8b

88÷8=11

8 0

3 years ago

According to Professor Robinson, which of the following aspects of A Streetcar Named Desire can be said to reflect elements of T

natita [175]

The best and most correct answer among the choices provided by the first question is letter E which is all of the above.

On the other hand, the best and most correct answer among the choices provided by the second question is letter A which is rebirth and coming death.

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!

7 0

3 years ago

What is the slope of the line through the points (-2, -1) and (4, 3)?

Natalka [10]

Answer:

#2 option: $\frac{2}{3}$

Step-by-step explanation:

$slope=\frac{rise}{run} =\frac{y^2-y^1}{x^2-x^1}$

$\frac{3-(-1)}{4-(-2)}=\frac{-4}{-6} =\frac{-2}{-3} =\frac{2}{3}$

= $\frac{2}{3}$

8 0

2 years ago

Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so

IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

Solution:

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

$14 \times c + 5 \times v=119$

14c + 5v = 119 ------- eqn 1

Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

$10 \times c + 10 \times v = 130$

10c + 10v = 130 -------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

Subtract eqn 2 from eqn 3

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

Substitute c = 6 in eqn 1

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0

3 years ago

Find the y-intercept of x – 5y = 10.

aniked [119]

Change the equation to slope intercept form:
-5y=-x+10
y=1/5x-2

The y intercept is -2

7 0

3 years ago

Read 2 more answers