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frez [133]
3 years ago
14

A researcher for paint company is measuring the level of a certain chemical contained in a particular type of paint. If the pain

t contains too much of the chemical, the quality of the paint will be comprised. On average each can of paint contains 10 percent of the chemical. How many cans of paint should the sample contain if the researchers wants to be 98 percent certain of being within 1 percent of the true proportion of this chemical
Mathematics
1 answer:
Flauer [41]3 years ago
4 0

Answer:

get noob

Step-by-step explanation:

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What is the enlargement ratio if you enlarge the figure to have a width of 16 units and length of 12 units
Fantom [35]

Answer:

The enlargement ratio is 3:4

Step-by-step explanation:

We are given

a width of 16 units and length of 12 units

so,

W=16

and

L=12

now, we can find enlargement ratio

we can use formula

enlargement ratio = (length)/(width)

=\frac{L}{W}

now, we can plug values

=\frac{12}{16}

now, we can simplify it

=\frac{3}{4}

So,

The enlargement ratio is 3:4

6 0
3 years ago
Verify the identity 6cos^2(x) -3 = 3 - 6sin^2(x)
Lorico [155]

Answer:

It is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x .

Step-by-step explanation:

We already have the identity of x as \sin ^{2}x + \cos ^{2}x = 1 .......... (1)  .

So, from equation (1) we can write that

\cos ^{2} x = 1 - \sin ^{2} x

⇒ 6\cos ^{2} x = 6 - 6 \sin ^{2} x

⇒ 6\cos ^{2} x -3 = 6 - 6 \sin ^{2}x -3

⇒ 6\cos ^{2}x -3 = 3 - 6\sin ^{2} x

Hence, it is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x . (Answer)

5 0
3 years ago
A very large book is numbered to 1 to 11521 How many digits are used to print all these page numbers
stealth61 [152]

Answer:

46,499 digits

Step-by-step explanation:

Total pages of book = 11,521

9 pages numbered 1 - 9 that need 1 digit each = 9 × 1

= 9 digits

90 pages numbered 10 - 99 that need 2 digits each = 90 × 2

= 180 digits

900 pages numbered 100 - 999 that need 3 digits each = 900 × 3

= 2,700 digits

9000 pages numbered 1000 - 9999 that need 4 digits each = 9000 × 4

= 36,000 digits

1522 pages numbered 1000 - 11521 that need 5 digits each = 1522 × 5

= 7,610 digits

Total digits needed = 9 digits + 180 digits + 2,700 digits + 36,000 digits + 7,610 digits

= 46,499 digits

5 0
3 years ago
PART B, 50 POINTS IF RIGHT!​
AfilCa [17]

Answer:

I believe the correct answer is B! Hope this helped.

6 0
3 years ago
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