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Fiesta28 [93]
3 years ago
7

What is it called when a reading is converted into computer language? computerizing surveying digitizing converting

Physics
1 answer:
disa [49]3 years ago
3 0
Digitizing is the correct answer
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A ball is shot from the ground into the air. At a height of 8.8 m, the velocity is observed to be
Mariulka [41]

Answer:

h = 10.4 m

R = 22.48 m

v= 16,2 m/s , α = 61.7°, below the horizontal

v = (7.7)i + (-14.3)j in meters per second (i horizontal, j downward)

Explanation:

The ball describes a parabolic path, and the equations of the movement are:

Equation of the uniform rectilinear motion (horizontal ) :

x = vx*t  :

Equations of the uniformly accelerated rectilinear motion of upward   (vertical ).

y = (v₀y)*t - (1/2)*g*t² Equation (2)

vfy² = v₀y² -2gy Equation (3)

vfy = v₀y -gt Equation (4)

Where:  

x: horizontal position in meters (m)

t : time (s)

vx: horizontal velocity  in m  

y: vertical position in meters (m)  

v₀y: initial  vertical velocity  in m/s  

vfy: final  vertical velocity  in m/s  

g: acceleration due to gravity in m/s²

Known data

y= 8.8 m

v = ( (7.7)i + (5.7)j  ) m/s : vx= 7.7 m/s , vy= 5.7 m/s

g = 9.8 m/s²

Calculation of the  initial  vertical velocity ( v₀y)

We apply Equation (3) with the known data

(vfy)² = (v₀y)² -2*g*y

(5.7)² = (v₀y)²- (2)*(9.8)*(8.8)

(5.7)²+ 172.48 =  (v₀y)²

v_{oy} = \sqrt{(5.7)^{2}+ 172.48 }

v₀y = 14.3 m/s

Calculation of the maximum height  the ball rise (h)

In the maximum height vfy=0

We apply the Equation (3) :

(vfy)² = (v₀y)² -2*g*y

0 = (14.3)² - 2*98*h

h = (14.3)² / 19.6

h = 10.4 m

Calculation of the time it takes for the ball to the maximum height

We apply the Equation (4) :

vfy = v₀y -gt

0 = v₀y -gt

gt = v₀y

t = v₀y/g

t = 14.3/9.8

t= 1.46 s

Flight time = 2t = 2.92 s

Total horizontal distance traveled by the ball  (R)

We replace data in the equation (1)

x =vx*t    vx= 7.7 m/s , t =2.92 s  (Flight time)

R = (7.7)* (2.92) = 22.48 m

Velocity of the ball (magnitude (v) and direction (α)) the instant before it hits the ground

vx = 7.7 m/s

vy = v₀y -gt = 14.3 - 9.8* (2.92) = -14.3 m/s

v= \sqrt{v_{x}^{2}+v_{y}^{2}  }

v= \sqrt{(7.7)^{2}+ (-14.3)^{2}  }

v= 16,2 m/s

\alpha = tan^{-1} (\frac{v_{y} }{v_{x} })

\alpha = tan^{-1} (\frac{-14.3 }{7.7 })

α = -61.7°

α = 61.7°, below the horizontal

i- j components of the v

v = (7.7)i + (-14.3)j in meters per second (i horizontal, j downward)

5 0
3 years ago
You drop a rock down a well and hear a splash 3 s later. As Charlie Brown would say, the well is 3 seconds deep. How fast is the
vampirchik [111]
Since it was dropped, it should be the speed of gravity which is 9.8 meters/second
5 0
2 years ago
When the sun and moon work together ____________ are formed on Earth.
Paha777 [63]

Answer:

C. Spring Tides is the answer.

7 0
2 years ago
Define the following terms.
grandymaker [24]

Answer:

I can only define a few of them, hope you don't mind.

Seismic- It means connected with or caused by earthquakes

Epicenter- It means the point on the earth's surface where the effects of an earthquake are most felt strongly.

Fault- A place where there is a break that is longer than usual in the layers of rock in the earth's crust.

Tectonic waves- Waves connected with the structure of the earth's surface.

Plate boundaries- The boundaries that differentiates the large sheets of rock (called PLATES) that form the earth's surface. Plate tectonics is the movement of the large sheets of rocks that form the earth's surface

3 0
2 years ago
Calculate the acceleration of a helium nucleus (charge +2e, where e-electronic charge), when it enters an electric field of stre
konstantin123 [22]

Answer:

3.8 x 10^10 m/s^2

Explanation:

Charge, q = 2 e =  2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C

Electric field strength, E = 790 N/C

mass of helium nucleus, m = 6.645 x 10^-27 Kg

the force due to electric filed on a charge particle is given by

F = q x E

Where, q be the charge on the charged particle and E be the strength of electric field.

By substituting the values

F = 3.2 x 10^-19 x 790

F = 2528 x 10^-19 N

According to the Newton's second law

F = m x a

Where, me be the mass and a be the acceleration

By substituting the values

2528\times 10^{-19}=6.645\times 10^{-27}\times a

a = 3.8 x 10^10 m/s^2

3 0
3 years ago
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