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3 years ago

What is it called when a reading is converted into computer language? computerizing surveying digitizing converting

Physics

1 answer:

disa [49]3 years ago

3 0

Digitizing is the correct answer

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An unstable atomic nucleus has a mass of 17.010-27kg, and starts out at rest. When it decays, it the original nucleus disintegra

slega [8]

Answer:

Part a)

$v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s$

Part b)

$E = 4.4 \times 10^{-13} J$

Explanation:

As per momentum conservation we know that there is no external force on this system so initial and final momentum must be same

So we will have

$m_1v_1 + m_2v_2 + m_3v_3 = 0$

$(5 \times 10^{-27})(6 \times 10^6\hat j) + (8.4 \times 10^{-27})(4 \times 10^6\hat i) + (3.6 \times 10^{-27}) v = 0$

$(30\hat j + 33.6\hat i)\times 10^6 + 3.6 v = 0$

$v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s$

Part b)

By equation of kinetic energy we have

$E = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 + \frac{1}{2}m_3v_3^2$

$E = \frac{1}{2}(5 \times 10^{-27})(6\times 10^6)^2 + \frac{1}{2}(8.4 \times 10^{-27})(4 \times 10^6)^2 + \frac{1}{2}(3.6 \times 10^{-27})(8.33^2 + 9.33^2) \times 10^{12}$

$E = 9\times 10^{-14} + 6.72 \times 10^{-14} + 2.82\times 10^{-13}$

$E = 4.4 \times 10^{-13} J$

8 0

3 years ago

A force of 19 newtons is applied on a cart of 2 kilograms, and it experiences a frictional force of 1.7 newtons. What is the acc

Umnica [9.8K]

Frictional force always opposes applied force, so the net force on the cart would have to be 19N - 1.7N. The acceleration can then be solved by using the relation: F = ma. This is shown below:

Net force = 19 - 1.7 = 17.3 N

Acceleration = Force / mass
Acceleration = 17.3 / 2
Acceleration = 8.65 N/m

4 0

3 years ago

Read 2 more answers

A healthy environment depends on biogeochemical cycles maintaining a balance of input and output. When forests are cut down, whi

Ann [662]

The correct answer will be c

8 0

3 years ago

Read 2 more answers

Why is the sky blue and doesn't change color

Softa [21]

The statement is <u>false</u> because the sky <u>can change </u>colors during sunsets, sun rises, etc. The sky is not always blue.

7 0

3 years ago

If planet i is 30.3 million miles farther from the sun than planet ii, then planet iii is 24.6 million miles farther from the s

kkurt [141]

Since the total distance for all three of the planets is 196.2 million miles, you would add planet i and planet iii, then subtract that number from 196.2

planet i and planet iii equaled 54.9 million miles, that subtracted from 196.2 equals 141.3

So your answer is 141.3 million miles

3 0

3 years ago