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erastova [34]
3 years ago
6

many different types of mutations can occur within the body .cystic fibrosis is a genetic disorder that is caused by different m

utations within the cftr gene
Biology
1 answer:
denpristay [2]3 years ago
8 0
<h3>Question from alternative source</h3>

Many different types of mutations can occur within the body. Cystic fibrosis is a genetic disorder that is caused by different mutations within the CFTR gene. One mutation in the CFTR gene that leads to cystic fibrosis causes translation to end earlier in the gene sequence. Which type of mutation causes this translation error that leads to cystic fibrosis?

  • silent
  • missense
  • nonsense
  • deletion

Answer:

Nonsense

Explanation:

Nonsense mutations describe mutations that produce a premature stop codon. The stop codons are UAG, UAA, and UGA. A way in which this could arise is, for example, if there was a substution of a nucleotide in the mRNA codon UAC (which codes for the amino acid Tyrosine) to the nucleotide UAG (which codes for a stop codon).

The translation machinery would reach this codon, which signals that translation should be terminated. This would mean that the mRNA would be released, and a truncated (shortened) version of the amino acid would be produced. This is likely to be non-functional, and may even be marked for destruction by the cell.

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Explanation:

<em>Let the ability to break down the red color in beets be represented by the allele </em><em>B</em><em>. The inability would be represented by the allele </em><em>b</em><em>.</em>

A nonsecretor's genotype would be BB or Bb while a secretor's genotype would be bb.

A nonsecretor woman with a secretor father would be a carrier with genotype Bb. A nonsecretor man who in a previous marriage had a secretor daughter would also be a carrier with genotype Bb. If the two marries:

            <em>Bb     x     Bb</em>

<em>            BB    2Bb    bb</em>

1.

(a) probability of their first child will be a secretor girl = probability of having a girl and being a secretor.

Probability of having a girl = 1/2

Probability of being a secretor = 1/4

<em>probability of their first child will be a secretor girl</em> = 1/2 x 1/4 = 1/8

(b) Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor.

Probability of having a girl = 1/2

Probability of being a nonsecretor = 3/4

<em>Probability of their first child being a nonsecretor girl = probability of having a girl and being a nonsecretor</em> = 1/2 x 3/4 = 3/8

2. <em>Probability that their first two children will be nonsecretors of either sex = probability of their first being a nonsecretor and of either sex and probability of their second being a nonsecretor and of either sex.</em>

  = 3/4 x 3/4 = 9/16

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Explanation:

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