Answer: v2=331.289mL
Explanation:
Formula for ideal gas law is p1v1/T1=p2v2/T2
P1=782.3mmHg
P2=769mmHg at STP
V1=362.4mL
V2=?
T1=273+34.4=307.4k
T2=273k at STP
Then apply the formula and make v2 the subject of formula
V2= 782.3×362.4×273/760×307.4
V2=77397006.96/233624
V2=331.289mL
The answer is (2). Heat always flows down the temperature gradient, from high temperature to low temperature. Therefore, since the person is the warmest, heat flows from the person to both the ice and the air. Additionally, since the air is warmer than the ice, heat flows from the air to the ice.
<span>4 Al + 3 O2 → 2 Al2O3
(10.0 g Al) / (26.98154 g Al/mol) = 0.37062 mol Al
(19.0 g O2) / (31.99886 g O2/mol) = 0.59377 mol O2
0.37062 mole of Al would react completely with 0.37062 x (3/4) = 0.277965 mole of O2, but there is more O2 present than that, so O2 is in excess.
((0.59377 mol O2 initially) - (0.277965 mol O2 reacted)) x (31.99886 g O2/mol) =
10.1 g O2 left over</span><span>
</span>
Answer:
I think the answer would be A.
