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Inga [223]
3 years ago
11

What structure is used to focus light in a reflecting telescope?

Physics
1 answer:
zmey [24]3 years ago
4 0

Answer:

Concave mirror

Explanation:

  • Reflecting telescopes is a type of telescope that uses mirrors instead of lens. This is because mirrors are lighter and thus are easier to make perfectly smooth as compared to lenses.
  • Reflecting telescopes use concave mirrors for the purposes of bringing light gathered to a certain focus.
  • <em><u>Concave mirror in reflecting telescopes collects parallel rays from the object and forms an image at the focal point. </u></em>

<em><u /></em>

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I think its D not sure
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4 years ago
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Lori wants to send a box of oranges to a friend by mail. The box of oranges cannot exceed a mass of 10.222 Kg. If each orange ha
Sergeu [11.5K]

Explanation:

Given that,

The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.

The mass of each orange is 198 g

We know that,

1 kg = 1000 g

10.222 kg = 10.222×1000 g

Let there are n number of oranges. So,

n=\dfrac{10.222\times 1000\ g}{198\ g}\\\\n=51.92\approx 52\ \text{oranges}

It means she can send 52 oranges and it is maximum quantity.

4 0
3 years ago
What do we call the principal SI units that are used to derive all other SI units? Question 3 options:
Angelina_Jolie [31]

Answer: Base units

The principal SI units that are used to derive all other SI units are called base units. The base units are the units of fundamental quantities e.g.  M L T that is Mass, Length, and Time. All other physical quantities can be written in the fundamental dimension forms. The physical quantities are not measured directly but are build up from the building blocks that are the fundamental quantities which have base units.

5 0
3 years ago
Qual a capacidade térmica de um objeto que, ao receber 10000 cal de energia, tem sua temperatura elevada de 25°C para 75°C?
Stolb23 [73]

Answer:

200 cal/^{\circ}C

Explanation:

When heat energy is supplied to an object, the temperature of the object increases according to the equation:

Q=C\Delta T

where

Q is the heat supplied

C is the heat capacity of the object

\Delta T is the change in temperature

In this problem we have:

Q=10,000 cal is the energy supplied

\Delta T=75C-25C=50C is the change in temperature of the object

Therefore, the heat capacity of the object is:

C=\frac{Q}{\Delta T}=\frac{10,000}{50}=200 cal/^{\circ}C

6 0
3 years ago
Hartman value profile
Grace [21]
What is your question exactly? I'm confused?
6 0
4 years ago
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