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Inga [223]
2 years ago
11

What structure is used to focus light in a reflecting telescope?

Physics
1 answer:
zmey [24]2 years ago
4 0

Answer:

Concave mirror

Explanation:

  • Reflecting telescopes is a type of telescope that uses mirrors instead of lens. This is because mirrors are lighter and thus are easier to make perfectly smooth as compared to lenses.
  • Reflecting telescopes use concave mirrors for the purposes of bringing light gathered to a certain focus.
  • <em><u>Concave mirror in reflecting telescopes collects parallel rays from the object and forms an image at the focal point. </u></em>

<em><u /></em>

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A 1,600 kg train car rolling freely on level track at 16 m/s bumps into a 1.0 × 103 kg train car moving at 10.0 m/s in the same
emmainna [20.7K]
This item is solved through the concept of the conservation of momentum which states that the momentum before and after collision should be equal. 
                                   momentum = mass x velocity
            (1,600 kg)(16 m/s) + (1.0x10^3 kg)(10 m/s) = (1600 + 1000 kg)(x)
The value of x is 13.69 m/s. Thus, their final speed is approximately letter D. 14 m/s. 
6 0
3 years ago
A ball is thrown straight up with an initial velocity of 6.4 m/s. It travels for 0.64 seconds, and has a change of position of 2
Naya [18.7K]

Answer:

V = 0.9 m/s

Explanation:

The parameters given are:

Initial velocity U = 6.4 m/s

Time t = 0.64s

Height h = 2.05 m

To find the final velocity, let us use third equation of motion

V^2 = U^2 - 2gH

Since the ball is going upward, g will be negative

Substitute all the parameters into the formula

V^2 = 6.4^2 - 2 × 9.8 × 2.05

V^2 = 40.96 - 40.18

V^2 = 0.78

V = sqrt( 0.78)

V = 0.883 m/ s

V = 0.9 m/ s approximately

6 0
3 years ago
The distance between two charged objects is doubled. What happens to the electrostatic force between the two?a)It will double.b)
zzz [600]

Answer:

d) It will be cut to a fourth of the original force.

Explanation:

The magnitude of the electrostatic force between the charged objects is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the separation between the two objects

In this problem, the initial distance is doubled, so

r' = 2r

Therefore, the new electrostatic force will be

F=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}(k\frac{q_1 q_2}{r^2})=\frac{1}{4}F

So, the force will be cut to 1/4 of the original value.

5 0
3 years ago
How can resistance be useful and where can they be useful?
sergiy2304 [10]
-- Resistance can be useful among the population of a repressive government.
Although it can be dangerous for those who resist, it can also exert pressure
against the regime to alter its repressive practices.

-- Resistance can also be useful in electronic circuits. "Lumped" components with
known numerical values of resistance are used to divide voltage, limit current, and
dissipate controlled amounts of electrical energy. 
3 0
2 years ago
a bicycle travels at a velocity of -2.33 m/s and has a displacement of -58.3 m. how much time did it take?
Alexandra [31]
We know that velocity is equal to the total displacement of an object over time.
velocity =  \frac{displacement}{time}
Deriving from that equation, we can say that:
t =  \frac{d}{v}
Okay, so here it goes:
t =  \frac{58.3m}{2.33 \frac{m}{s} } \\ t = 25.02s
The bicycle took 25.02 seconds to displace at 58.3 meters.
5 0
3 years ago
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