Question

A block of mass 5 kg slides down an inclined plane that has an angle of 10. If the inclined plane has no friction and the block starts at a height of 0.8 m, how much kinetic energy does the block have when it reaches the bottom? Acceleration due to gravity is g = 9.8 m/s2

Answer 1

The kinetic energy of the block  when it reaches the bottom is 39.2 J.

Kinetic energy of the block at the bottom

Apply the principle of conservation of energy.

K.E(bottom) = P.E(top)

P.E(top) = mgh

where;

• m is mass of the block
• g is acceleration due to gravity
• h is the vertical height of fall

P.E(top) = 5 x 9.8 x 0.8

P.E(top) = K.E(bottom) = 39.2 J

Learn more about kinetic energy here: brainly.com/question/25959744

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