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Alekssandra [29.7K]
2 years ago
11

A block of mass 5 kg slides down an inclined plane that has an angle of 10. If the inclined plane has no friction and the block

starts at a height of 0.8 m, how much kinetic energy does the block have when it reaches the bottom? Acceleration due to gravity is g = 9.8 m/s2
Physics
1 answer:
Westkost [7]2 years ago
4 0

The kinetic energy of the block  when it reaches the bottom is 39.2 J.

<h3>Kinetic energy of the block at the bottom</h3>

Apply the principle of conservation of energy.

K.E(bottom) = P.E(top)

P.E(top) = mgh

where;

  • m is mass of the block
  • g is acceleration due to gravity
  • h is the vertical height of fall

P.E(top) = 5 x 9.8 x 0.8

P.E(top) = K.E(bottom) = 39.2 J

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

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Answer:

Explanation:

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∫B.dl = B x 2πr  

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<span>mountain observatory is placed at an altitude worth 2920 m asl

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A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i
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Answer:

The minimum speed must the car must be 13.13 m/s.

Explanation:

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We know that, mg be the weight of car and rider, which is equal to the centripetal force.

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