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3 years ago

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In these formulas, it is useful to understand which variables are parameters that specify the nature of the wave. The variables

E0E0E_0 and B0B0B_0 are the __________ of the electric and magnetic fields. Choose the best answer to fill in the blank.

1 answer:

Juli2301 [7.4K]3 years ago

7 0

They made me do it I don’t even know what to say I’m so sorry

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A car speeding down the highway honks its horn, which has a frequency 392 Hz, but a resting bystander hears the frequency 440 Hz

Natali [406]

Answer:

37.42 m/s

Explanation:

We know that apparent frequency, $\bar f$ is given by

$\bar f=f\frac {V}{V-V_s}$ where f is the given frequency in this case 392, V is the speed of sound in air which is given as 343 and $V_s$ is the speed of car which is unknown, \bar f is given as 440 Hz

$440=392\times \frac {343}{343-V_s}\\343-V_s=392\times \frac {343}{440}=305.5818182\\V_s=343-305.5818182=37.41818182\approx 37.42 m/s$

8 0

3 years ago

A typical jet airliner has a cruise airspeed of 900 km/h , which is its speed relative to the air through which it is flying. If

Luba_88 [7]

Explanation:

It is given that,

Speed of the jet airplane with respect to air, $v_{PA} = 900\ km/h$

If the wind at the airliner’s cruise altitude is blowing at 100 km/h from west to east, $v_{AG}= 100\ km/h$

(A) Let $v_{PG}$ is the speed of the airliner relative to the ground if the airplane is flying from west to east,

$v_{PG}=900-100=800\ km/h$

(B) Let $v'_{PG}$ is the speed of the airliner relative to the ground if the airplane is flying from east to west,

$v'_{PG}=900+100=1000\ km/h$

Hence, this is the required solution.

8 0

3 years ago

a toy car has a 2.0 A current, and its resistance is 1.75 ohms. How much voltage does the car require

o-na [289]

Answer:

the answer will be 24.40 ohms law

Explanation:

5 0

3 years ago

A car accelerates horizontally from rest on a level road at a constant acceleration of Down the road, it passes through two phot

11Alexandr11 [23.1K]

Answer:i totally forgot how that works

Explanation:

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5 0

3 years ago

Read 2 more answers

A 1 200-kg car traveling initially at vCi 5 25.0 m/s in an easterly direction crashes into the back of a 9 000-kg truck moving i

sukhopar [10]

Answer:

The velocity of the truck after the collision is 20.93 m/s

Explanation:

It is given that,

Mass of car, m₁ = 1200 kg

Initial velocity of the car, $v_{Ci}=25\ m/s$

Mass of truck, m₂ = 9000 kg

Initial velocity of the truck, $v_{Ti}=20\ m/s$

After the collision, velocity of the car, $v_{Cf}=18\ m/s$

Let $v$ is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.

$initial\ momentum=final\ momentum$

$1200\ kg\times 25\ m/s+9000\ kg\times 20\ m/s=1200\ kg\times 18+9000\ kg\times v$

$210000-21600=9000\ kg\times v$

$v=20.93\ m/s$

So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.

8 0

3 years ago