Answer:
v = 1.25 m/s
Explanation:
We have,
Distance covered by a person is 10 meters
Time taken by him to cover that distance is 8 seconds.
If we want to find the speed of a person, we must know distance covered by it and taken. In this case, we know both distance and time. His speed is given by :

So, the speed of the person is 1.25 m/s.
 
        
             
        
        
        
funny, actually, i'm a hydraulic, and pneumatic cylinder, pump, and line system mechanic, and the answer is pressure.... pressure builds up from the hydraulic pump, and then transfers through hoses to extend, and contract the cylinders by filling them with hydraulic fluid, and vice versa for contracting them.
hope this helps!
 
        
                    
             
        
        
        
Answer:
    Force required to accelerate = 794.44 N
Explanation:
  Force required = Mass of horse x Acceleration of horse
  Mass of horse and rider, m=   572 kg
  Acceleration of horse and rider, a = 5 kph per second 
                                       
   Force required = ma
                              = 572 x 1.39 = 794.44 N
   Force required to accelerate = 794.44 N
 
        
             
        
        
        
Answer:
6858.5712 m/s
Explanation:
Given that:
Radius, r
R = 3.20 * 10^3.
Normal force = 0.5 * normal weight
Normal force = Fn ; Normal weight = Fg
Fn = 0.5Fg
Recall:
mv² / R = Fn + Fg
Fn = 0.5Fg
mv² / R = 0.5Fg + Fg
mv² /R = 1.5Fg
mv² = 1.5Fg * R
F = mg
mv² = 1.5* mg * R
v² = 1.5gR
v = sqrt(1.5gR)
V = sqrt(1.5 * 9.8 * 3.2 * 10^3)
V = sqrt(47.04^3)
V = 6858.5712 m/s
 
        
             
        
        
        
Answer:
A)     K / K₀ = 4   b)     v / v₀ = 4
Explanation:
A) For this exercise we can use the conservation of mechanical energy
in the problem it indicates that the displacement was doubled (x = 2xo)
starting point. At the position of maximum displacement
       Em₀ = Ke = ½ k (2x₀)²
final point. In the equilibrium position
        = K = ½ m v²
 = K = ½ m v²
         Em₀ = Em_{f}
         ½ k 4 x₀² = K
         (½ K x₀²) = K₀
          K = 4 K₀
           K / K₀ = 4
B) the speed value
           ½ k 4 x₀² = ½ m v²
           v = 4 (k / m) x₀
if we call
            v₀ = k / m x₀
           v = 4 v₀
          v / v₀ = 4