Ask question

Ask question

All categories

3 years ago

5

In these formulas, it is useful to understand which variables are parameters that specify the nature of the wave. The variables

E0E0E_0 and B0B0B_0 are the __________ of the electric and magnetic fields. Choose the best answer to fill in the blank.

1 answer:

Juli2301 [7.4K]3 years ago

7 0

They made me do it I don’t even know what to say I’m so sorry

You might be interested in

Density is determined by:

Irina18 [472]

The mass of an object divided by its volume

3 0

3 years ago

What fraction of a piece of concrete will be submerged when it floats in mercury? the density of concrete is 2.3×103kg/m3 and de

chubhunter [2.5K]

<span>17% Any object that is floating will display the volume of fluid that matches the mass of the object that's floating. So if the object is 100% as dense as the fluid, it will just barely sink, if it's 50% as dense as the fluid, 50% will be submerged, etc. So let's see what percent of mercury's density is concrete. 2.3x10^3 / 13.6x10^3 = 0.169117647 = 16.9117647% Rounding to 2 significant figures gives 17%. So 17% of a piece of concrete will be submerged in mercury when it's floating in mercury.</span>

3 0

3 years ago

Two coherent sources of radio waves, A and B, are 5.00 metersapart. Each source emits waves with wavelength 6.00 meters.Consider

alexgriva [62]

Answer

given,

distance between A and B is equal to 5 m

let x be the distance of loud speaker from the source A

For constructive interference, path difference = mλ

x - (5 - x ) = 0 , for m = 0

2 x - 5 = 0

2 x = 5

x = 2.5 cm

For destructive interference

$|x - (5 - x )| = (2 m + 1)\dfrac{\lambda}{2}$

m = 0

$|2x - 5| = \dfrac{\lambda}{2}$

$|2x - 5| = \dfrac{6}{2}$

$\pm(2x - 5) = 3$

x = 4 , 1 cm

3 0

3 years ago

What is the average acceleration of the object represented in the graph above over the 10 seconds? I know the answer isn’t C

polet [3.4K]

It's always a good idea to start with the definition of the thing you're trying to find.

This problem is just trying to find out whether you KNOW the definition of acceleration. You may know it, but you haven't used it yet.

Average acceleration = (change in velocity) divided by (total time).

Change in velocity = (end value) minus (start value)

Change in velocity = (20m/s) - 0

Change in velocity = 20 m/s

Time = 10 s

Average acceleration = (20m/s)/(10s)

Average acceleration = 2 m/s^2

3 0

3 years ago

Read 2 more answers

A lamp has a current of 2.17 A. In hours, how long does it take for 1 mole of electrons to pass through the lamp?

Gennadij [26K]

<u>Answer:</u> The amount of time needed for 1 mole of electrons to pass through the lamp is 12.33 hrs.

<u>Explanation:</u>

We are given:

Moles of electron = 1 mole

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=9.6352\times 10^4C$

To calculate the time required, we use the equation:

$I=\frac{q}{t}$

where,

I = current passed = 2.17 A

q = total charge = $9.6352\times 10^4C$

t = time required = ?

Putting values in above equation, we get:

$2.17A=\frac{9.6352\times 10^4C}{t}\\\\t=\frac{9.6352\times 10^4C}{2.17A}=44402s$

Converting this into hours, we use the conversion factor:

1 hr = 3600 seconds

So, $44402s\times \frac{1hr}{3600s}=12.33hr$

Hence, the amount of time needed for 1 mole of electrons to pass through the lamp is 12.33 hrs.

3 0

3 years ago