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DanielleElmas [232]
3 years ago
12

A sample of an unknown liquid has a volume of 12.0 mL and a mass of 6 g. What is its density? Show your work or explain how you

determined this value
Physics
2 answers:
Iteru [2.4K]3 years ago
8 0
The answer is 6.12 L
Inessa [10]3 years ago
6 0

Answer:

Density, d = 0.5 g/mL

Explanation:

It is given that,

Mass of the unknown liquid, m = 6 g

Volume of unknown liquid, V = 12 mL

Density is defined as the mass of the liquid divided by its volume. Mathematically, it is given by :

d=\dfrac{m}{V}

d=\dfrac{6\ g}{12\ mL}

d = 0.5 g/mL

So, the density of the unknown liquid is 0.5 g/ml. Hence, this is the required solution.

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Determine the mass [kg] of the compressed air in a scuba diving tank given the following information. The internal volume of the
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m=2473.5 kg

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4 years ago
A simple pendulum is 3.00 m long. (a) What is the period of small oscillations for this pendulum if it is located in an elevator
aliina [53]

Answer:

a,)3.042s

b)4.173s

c)3.281s

Explanation:

For a some pendulum the period in seconds T can be calculated using below formula

T=2π√(L/G)

Where L = length of pendulum in meters

G = gravitational acceleration = 9.8 m/s²

Then we are told to calculate

(a) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 3.00 m/s2?

Since oscillations for this pendulum is located in the elevator that is accelerating upward at 3.00 then

use G = 9.8 + 3.0 = 12.8 m/s²

Period T=2π√(L/G)

T= 2π√(3/12.8)

T=3.042s

b) (b) What is the period of small oscillations for this pendulum if it is located in an elevator accelerating downward at 3.00 m/s2?

G = 9.8 – 3.0 = 6.8 m/s²

T= 2π√(3/6.8)

T=4.173s

C)(c) What is the period of this pendulum if it is placed in a truck that is accelerating horizontally at 3.00 m/s2?

Net acceleration is

g'= √(g² + a²)

=√(9² + 3²)

Then period is

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5 0
4 years ago
A wire 25.0cm long lies along the z-axis and carries a current of 9.00A in the positive +z-direction. The magnetic field is unif
marysya [2.9K]

The expression of the magnetic force and solving the determinant allows to shorten the result for the value of the magnetic force are:

  • In Cartesian form  F = 2.46 i ^ - 0.605 j ^
  • In the form of magnitude and direction F = 2.53 N and θ = 346.2º

Given parameters.

  • Length of the wire on the z axis is: L = 25.0 cm = 0.25 m.
  • The current i = 9.00 A in the positive direction of the z axis.
  • The magnetic field B = (-0.242 i ^ - 0.985 j ^ -0.336 k ^ ) T

To find.

  • Magnetic force.

The magnetic force on a wire carrying a current is the vector product of the direction of the current and the magnetic field.

          F = i L x B

Where the bold letters indicate vectors, F is the force, i the current, L a vector pointing in the direction of the current and B the magnetic field.

The best way to find the force is to solve the determinant, in general, a vector (L) is written in the form of the module times a <em>unit vector</em>.

         F= i |L| \left[\begin{array}{ccc}i&j&k\\L_x&L_y&L_z\\B_x&B_y&B_z\end{array}\right]  

Let's calculate.

       F= 9.00  \ 0.25 \ \left[\begin{array}{ccc}i&j&k\\0&0&1\\-0.242&-0.985&-0.336\end{array}\right]  

       F = 2.26 \ ( - 1 B_y i  \   + 1 B_x j  \ )  

       F = 2.5 (0.985 i ^ - 0.242 j ^)

       F = ( 2.46 i ^ - 0.605 j^ ) N

To find the magnitude we use the Pythagorean theorem.

        F = \sqrt{F_x^2 + F_y^2}  

        F = \sqrt{2.46^2 + 0.605^2}  

        F = 2.53 N

Let's use trigonometry for the direction.

        Tan θ ’= \frac{F_y}{F_x}  

        θ'= tan⁻¹ \frac{F_y}{F_x}  

        θ'= tan⁻¹1 (\frac{-.605}{2.46} )

        θ’= -13.8º

To measure this angle from the positive side of the x-axis counterclockwise.

        θ = 360- θ'

        θ = 360 - 13.8

        θ = 346.2º

In conclusion using the expression of the magnetic force and solving the determinant we can shorten the result for the value of the force are:

  • In Cartesian form    F = 2.46 i ^ - 0.605 j ^
  • In the form of magnitude and direction  F = 2.53 N and θ = 346.2º

Learn more here:  brainly.com/question/2630590

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3 years ago
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