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defon
4 years ago
10

If a person weighs 717 N on earth and 5320 N on the surface of a nearby planet, what is the acceleration due to gravity on that

planet?
Physics
1 answer:
Feliz [49]4 years ago
8 0

<u>Answer:</u>

The acceleration due to gravity on that planet = 72.76 m/s^2

<u>Explanation:</u>

  Weight of person in earth = 717 N

  We know that weight = mg

   Acceleration due to gravity of earth = 9.8m/s^2

   So mass of person = 717/9.8 = 73.16 kg

   Mass of body is constant everywhere, so mass of person on the surface of a nearby planet = 73.16 kg

   Weight on the surface of a nearby planet = 5320 N = mg', where g' is the acceleration due to gravity value of the nearby planet.

     So   5320 = 73.16*g'

                   g' = 72.76 m/s^2

   The acceleration due to gravity on that planet = 72.76 m/s^2

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Fiesta28 [93]

Answer:

 V₁ = 6 V ,  V₂ = V₃ = 3 V

Explanation:

To solve this circuit we must remember that there are two fundamental types of construction in series and parallel.

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in this circuit the constant current in the entire circuit and the voltage is the sum of the voltage of each term

* Parallel circuit in this there are two or more paths for the current

in this circuit the voltage is constant and the east is divided between each branch

with these principles let's analyze the proposed circuit

The DC battery is in parallel with resistor R1 and the equivalent of the other branch,

as in a parallel circuit the voltage is constant

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in the other branch (23) it forms a series construction, where the current is constant

               6 = iR₂ + iR₃

as they indicate that each resistance has the same value

              6 = 2 iR

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3 0
3 years ago
A 0.5-kg ball moving at 5 m/s strikes a wall and rebounds in the opposite direction with a speed of 2 m/s. If the impulse occurs
mart [117]

<em>Given that:</em>

                       mass of the ball (m) = 0.5 Kg ,

                    ball strikes the wall (v₁) = 5 m/s ,

rebounds in opposite direction (v₂) = 2 m/s,

                                time duration (t) = 0.01 s,

        <em> Determine the force (F) = ?</em>

We know that from Newton's II law,

                                <em>F = m. a</em>  Newtons  

                                  (velocity acting in opposite direction, so <em>a = ( (v₁ + v₂)/t</em>

                                   = m × (v₁ + v₂)/t

                                   = 0.5 × (5 + 2)/0.01

                                  = 350 N

<em>The force acting up on the ball is 350 N</em>

                                     

6 0
3 years ago
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Marizza181 [45]
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3 years ago
_____ occurs when a subject opens there eyes and devotes their attention to an object and the eeg rhythm changes to fast, irregu
slega [8]

Answer: B. Alpha block

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3 years ago
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igomit [66]

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im not very sure but i think this is how you do this

4 0
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