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3 years ago

The vapor pressure of ethanol at 25°C is 7.828 kPa . Calculate the vapor pressure in atm .

1 answer:

8 0

<span>First you get 7.83 kPa = 7.83 * 10^4 Pa Then convert it to atm by using the relation 1 Pa = 9.8692 * 10^-6 atm, this gives you 7.83 kPa = 7.83 * 10^4 * 9.8692 * 10^-6 atm = 77.275836 * 10^-2 atm = 0.77275836 atm Now round to three significant digits, = 0.773 atm</span>

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The volume of a sample gas, initially at 25 C and 158 mL, increased to 450 mL. What is the final temperature of the sample of ga

Rashid [163]

Answer:

Final temperature of the gas is 576 $^{0}\textrm{C}$ .

Explanation:

As the amount of gas and pressure of the gas remains constant therefore in accordance with Charles's law:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

where $V_{1}$ and $V_{2}$ are volume of gas at $T_{1}$ and $T_{2}$ temperature (in kelvin scale) respectively.

Here $V_{1}=158mL$ , $T_{1}=(273+25)K=298K$ and $V_{2}=450mL$

So $T_{2}=\frac{V_{2}T_{1}}{V_{1}}=\frac{(450mL)\times (298K)}{(158mL)}=849K$

849 K = (849-273) $^{0}\textrm{C}$ = 576 $^{0}\textrm{C}$

So final temperature of the gas is 576 $^{0}\textrm{C}$ .

3 0

3 years ago

Calculează masa zaharului si volumul apei necesare pentru prepararea 500g de soluție de zahăr cu partea de masa 20%

Sedbober [7]

T = 20 % : 20 / 100 = 0.2

m1 = solute

m2 = Solvent

T = m1 / m1 + m2

0.2 = 500 g / 500 g + m2

0.2 * ( 500 + m2 ) = 500

0.2 * 500 + 0.2 m2 = 500

100 + 0.2 m2 = 500

0.2 m2 = 500 - 100

0.2 m2 = 400

m2 = 400 / 0.2

m2 = 2000 g of water

hope this helps!

7 0

3 years ago

Hi um

nydimaria [60]

It’s( A)Condensation

6 0

3 years ago

Read 2 more answers

15.0 mL of an unknown clear liquid is added to a 50 mL graduated cylinder. The mass of the liquid is determined to be 12.7 grams

sveticcg [70]

Answer:

$\boxed {\tt A. \ d=0.85 \ g/mL}$

Explanation:

Density is found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass of the liquid is 12.7 grams.

We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.

$m= 12.7 \ g\\v= 15 \ mL$

Substitute the values into the formula.

$d=\frac{12.7 \ g}{ 15 mL}$

Divide.

$d=0.846666667 \ g/mL$

Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.

$d \approx 0.85 \ g/mL$

The density of the liquid is about 0.85 grams per milliliter and choice A is correct.

4 0

3 years ago

There are only two isotopes of gallium: ^69Ga (68.926 amu) and ^71Ga(70.025 amu). The average atomic mass of gallium is 69.723 a

SVEN [57.7K]

The question ask for the percentage of the abundance of galium-69 where there is two isotopes of galium: the 69Ga and the 71Ga. The average atomic mass of gallium is 69.723 amu. So the formula would be <span>69.723amu=(%x)∗(68.926amu)+(1−%x)∗(70.025amu) and the answer to this is 1.58%</span>

3 0

2 years ago