If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol
<h3>What is an ideal gas equation?</h3>
The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.
An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
Given :
The ideal gas equation is given below.
n = PV/RT
n = 86126.25 x 0.0024 / 8.314 x 287
n = 0.622 / molar mass (n = Avogardos number)
Molar mass = 7.18 g
Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g
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An ionic compound that results from the reaction of an acid and a base is called a(n) salt. the cation in this compound comes from the base while the anion comes from the acid.
When an acid and a base are together, they react to counteract each other's effects and create a salt.
Water is created when the OH(-) anion of the base and the H(+) cation of the acid mix.
A salt is a substance that is created when an anion from an acid and a base combine.
Common table salt, NaCl, is created when sodium hydroxide and hydrochloric acid are combined.
The positive ion (cation) of a base and the negative ion (anion) of an acid make up a salt.
A neutralizing reaction occurs when an acid and a base interact. Additionally, sodium chloride, generally known as table salt, is referred to as salt.
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Answer:
V₂ = 27 L
Explanation:
Given data:
Initial volume = 15 L
Initial temperature = 125 K
Final temperature = 225 K
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 15 L × 225K / 125 k
V₂ = 3375 L.K / 125 K
V₂ = 27 L
Answer:
9 moles of NaNO3 is obtained
Explanation:
The balanced chemical reaction equation for the reaction is;
Al(NO3)3 + 3NaCl-------> 3NaNO3 + AlCl3
Now, we have to determine the limiting reactant. The limiting reactant yields the least amount of NaNO3.
1 mole of Al(NO3)3 yields 3 moles of NaNO3
4 moles of Al(NO3)3 yields 4 * 3/1 = 12 moles of NaNO3
Also,
3 moles of NaCl yields 3 moles of NaNO3
9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO3
Hence, NaCl is the limiting reactant and 9 moles of NaNO3 is obtained.
