Which universal force acts on protons and neutrons in an atom's nucleus?
2 answers:
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The power is 833.3 W
Explanation:
First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:
where
mg = 1250 N is the weight of the barbell
h = 2 m is the change in height
Substituting,
Now we can calculate the power, which is equal to the work done per unit time:
where
W = 2500 J is the work done
t = 3 s is the time taken
Substituting,
Learn more about power:
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The picture shows it has a real life something to display conservation of energy with kinetic energy and potential energy.
Five sentences are for potential and kinetic energy. Potential energy is to energy an object when it stores. Kinetic energy is something to motion. When the potential energy is slows down the potential energy it might be increases. As from the object when the speeds up and it is decreases to potential energy.
Kinetic energy is to calculated by KE= mass×velocity²/2 as a fraction.
Potential energy is to calculated by PE= mass×g×height.
And the another picture it has a <span>energy, kinetic energy, mechanical energy, conservation of energy.
</span>
Five sentences are for potential and kinetic energy. Potential energy is to energy an object when it stores. Kinetic energy is something to motion. When the potential energy is slows down the potential energy it might be increases. As from the object when the speeds up and it is decreases to potential energy.
Kinetic energy is to calculated by KE= mass×velocity²/2 as a fraction.
Potential energy is to calculated by PE= mass×g×height.
And the another picture it has a <span>energy, kinetic energy, mechanical energy, conservation of energy.
</span>
Answer:
Part a: When the road is level, the minimum stopping sight distance is 563.36 ft.
Part b: When the road has a maximum grade of 4%, the minimum stopping sight distance is 528.19 ft.
Explanation:
Part a
When Road is Level
The stopping sight distance is given as
Here
- SSD is the stopping sight distance which is to be calculated.
- u is the speed which is given as 60 mi/hr
- t is the perception-reaction time given as 2.5 sec.
- a/g is the ratio of deceleration of the body w.r.t gravitational acceleration, it is estimated as 0.35.
- G is the grade of the road, which is this case is 0 as the road is level
Substituting values
So the minimum stopping sight distance is 563.36 ft.
Part b
When Road has a maximum grade of 4%
The stopping sight distance is given as
Here
- SSD is the stopping sight distance which is to be calculated.
- u is the speed which is given as 60 mi/hr
- t is the perception-reaction time given as 2.5 sec.
- a/g is the ratio of deceleration of the body w.r.t gravitational acceleration, it is estimated as 0.35.
- G is the grade of the road, which is given as 4% now this can be either downgrade or upgrade
For upgrade of 4%, Substituting values
<em>So the minimum stopping sight distance for a road with 4% upgrade is 528.19 ft.</em>
For downgrade of 4%, Substituting values
<em>So the minimum stopping sight distance for a road with 4% downgrade is 607.59 ft.</em>
As the minimum distance is required for the 4% grade road, so the solution is 528.19 ft.