The movement of the tectonic plates is caused by convection currents in Earth´s mantle.
Answer: A) convection currents in Earth´s mantle.
Answer:
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Explanation:
The corrosion rate is the rate of material remove.The formula for calculating CPR or corrosion penetration rate is
![CPR=\frac{KW}{DAT}](https://tex.z-dn.net/?f=CPR%3D%5Cfrac%7BKW%7D%7BDAT%7D)
K= constant depends on the system of units used.
W= weight =485 g
D= density =7.9 g/cm³
A = exposed specimen area =100 in² =6.452 cm²
K=534 to give CPR in mpy
K=87.6 to give CPR in mm/yr
mpy
![CPR=\frac{KW}{DAT}](https://tex.z-dn.net/?f=CPR%3D%5Cfrac%7BKW%7D%7BDAT%7D)
![=\frac{534\times( 485g)\times( 10^3mg/g)}{(7.9g/cm^3) \times (100in^2)\times (24h/day)\times (365day/yr)\times 1yr}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B534%5Ctimes%28%20485g%29%5Ctimes%28%2010%5E3mg%2Fg%29%7D%7B%287.9g%2Fcm%5E3%29%20%5Ctimes%20%28100in%5E2%29%5Ctimes%20%2824h%2Fday%29%5Ctimes%20%28365day%2Fyr%29%5Ctimes%201yr%7D)
=37.4mpy
mm/yr
![CPR=\frac{KW}{DAT}](https://tex.z-dn.net/?f=CPR%3D%5Cfrac%7BKW%7D%7BDAT%7D)
![=\frac{87.6\times (485g)\times (10^3 mg/g)}{(7.9g/cm^3)\times (100in^2)\times(2.54cm/in)^2\times (24h/day)\times (365day/yr)\times 1yr}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B87.6%5Ctimes%20%28485g%29%5Ctimes%20%2810%5E3%20mg%2Fg%29%7D%7B%287.9g%2Fcm%5E3%29%5Ctimes%20%28100in%5E2%29%5Ctimes%282.54cm%2Fin%29%5E2%5Ctimes%20%2824h%2Fday%29%5Ctimes%20%28365day%2Fyr%29%5Ctimes%201yr%7D)
=0.952 mm/yr
Therefore the rate of corrosion 37.4 mpy and 0.952 mm/yr.
Answer:
an electromagnetic wave with a wavelength in the range 0.001–0.3 m, shorter than that of a normal radio wave but longer than those of infrared radiation. Microwaves are used in radar, in communications, and for heating in microwave ovens and in various industrial processes.
Answer:
Yes, if the system has friction, the final result is affected by the loss of energy.
Explanation:
The result that you are showing is the conservation of mechanical energy between two points in the upper one, the energy is only potential and the lower one is only kinetic.
In the case of some type of friction, the change in energy between the same points is equal to the work of the friction forces
= ΔEm
=
-Em₀
As we can see now there is another quantity and for which the final energy is lower and therefore the final speed would be less than what you found in the case without friction.
=
+ Em₀
Remember that the work of the rubbing force is negative, let's write the work of the rubbing force explicitly, to make it clearer
½ m v² = -fr d + mgh
v = √(-fr d 2/m + 2 gh)
v = √ (2gh - 2fr d/m)
Now it is clear that there is a decrease in the final body speed.
Consequently, if the system has friction, the final result is affected by the loss of energy.