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Yakvenalex [24]

3 years ago

12

An earthquake creates a type of wave that shakes the ground. If a large earthquake occurs in Greece, how can the waves be felt a

cross the sea in Italy?

1 answer:

Cloud [144]3 years ago

7 0

The sound waves travel through the sea which creates movement which can be felt all the way in Italy in the sea- like a domino effect

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A motor produces less mechanical energy than the energy it uses because the motor?

In-s [12.5K]

<span>A motor produces less mechanical energy than the energy it uses because the motor looses some energy to heat.</span>

3 0

3 years ago

In an RC circuit, what fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for

4vir4ik [10]

Answer:

The fraction fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for 3.0 time constants is

$k = 0.903$

Explanation:

From the question we are told that

The time constant $\tau = 3$

The potential across the capacitor can be mathematically represented as

$V = V_o (1 - e^{- \tau})$

Where $V_o$ is the voltage of the capacitor when it is fully charged

So at $\tau = 3$

$V = V_o (1 - e^{- 3})$

$V = 0.950213 V_o$

Generally energy stored in a capacitor is mathematically represented as

$E = \frac{1}{2 } * C * V ^2$

In this equation the energy stored is directly proportional to the the square of the potential across the capacitor

Now since capacitance is constant at $\tau = 3$

The energy stored can be evaluated at as

$V^2 = (0.950213 V_o )^2$

$V^2 = 0.903 V_o ^2$

Hence the fraction of the energy stored in an initially uncharged capacitor is

$k = 0.903$

4 0

3 years ago

Which of the following types of light can humans see with their eyes?

Hitman42 [59]

Humans can not see any of the above with their eyes

7 0

3 years ago

Given a wire with a cross section of .45cm^2, a length of 3cm, and an internal resistance of 3 ohms, show your 5 steps to solve

Gre4nikov [31]

Resistance ∞ (proportional) length
resistance ∞ 1/ area

therefore,
(the constant that we take is known as the resistivity)

resistance = (resistivity*length )/ area
resistivity = (resistance * area ) / length
= (3 * 45) / 3 = 135/3 = 45 Ωm

in short your answer is 45 Ωm

4 0

3 years ago

The current through an inductor of inductance L is given by I(t) = Imax sin(ωt).

sammy [17]

Answer:

(a) $emf_L=-LI_{max}\omega cos(\omega t)$

(b) neither increasing or decreasing

(c) opposite to the flow of charge carriers

Explanation:

The current through an inductor of inductance L is given by:

$I(t)=I_{max}sin(\omega t)$ (1)

(a) The induced emf is given by the following formula

$emf_L=-L\frac{dI}{dt}$ (2)

You derivative the expression (1) in the expression (2):

$emf_L=-L\frac{d}{dt}(I_{max}sin(\omega t))\\\\emf_L=-LI_{max}\omega cos(\omega t)$

(b) At t=0 the current is zero

(c) At t = 0 the emf is:

$emf_L=-\omega LI_{max}$

w, L and Imax have positive values, then the emf is negative. Hence, the induced emf is opposite to the flow of the charge carriers.

(d) read the text carefully

6 0

3 years ago