Answer:
Size is not considered a physical property because it is not measurable with concrete data, but a compound of height, weight and volume, which are physical properties by their own.
A physical property is, according to an initial understanding, an individual property, that is, which is linked in particular to any substance.
A physical property has the characteristic of being able to be measured or observed without affecting the composition or integrity of the respective substance. Some examples of physical properties are mass and volume.
Answer: ro= 0.113
Explanation:
Data Given: Where D= Outer diameter
d= Inner diameter
ri= 0.4cm
r°= ?
Charge 1 and Charge 2 (q) = K i.e constant of proportionality
Where K = 1/4πe°. er; 3.2, ep; 2.6 ( Relative permeability)
(a) Approximate value size for the coaxial cable
C= 7.354 x Er/ Log 10 (D÷d)
C = 7.354 x 3.2/ Log 2.6
= 23.5/0.419
= 56.0cm
(b) Outer radius r° when dealing with 20kv
r°= impedance value (pie ÷ 20) d^2
r° = 2( π÷20)0.6^2
= 2( 0.1571) 0.36
r° = 0.113
(c) Assuming The Maximum Electric Field; Fmax = 25%
Given Vin = 25x10^6v/m, Vout = 20x 10^6 v/m.
Impedance p= √Vin x vout/ Z° (i)
Where Z° = electric surge ~25%
Subtituting Value of Vin & Vout In Equation (i)
P = 2.05x10^-8ohms
Note : Length of a conducting material determines the strength of dielectric material between the coaxial cable
Answer:
first one is - conduction
second one is - convection
I think <u>conduction </u>moves more easily
The source of energy that keeps the Sun shining today is _________.
<u>Is nuclear fusion</u>
~Hope this answers your question!~
Option(a) the mass of cart 2 is twice that of the mass of cart 1 is the right answer.
The mass of cart 2 is twice that of the mass of cart 1 is correct about the mass of cart 2.
Let's demonstrate the issue using variables:
Let,
m1=mass of cart 1
m2=mass of cart 2
v1 = velocity of cart 1 before collision
v2 = velocity of cart 2 before collision
v' = velocity of the carts after collision
Using the conservation of momentum for perfectly inelastic collisions:
m1v1 + m2v2 = (m1 + m2)v'
v2 = 0 because it is stationary
v' = 1/3*v1
m1v1 = (m1+m2)(1/3)(v1)
m1 = 1/3*m1 + 1/3*m2
1/3*m2 = m1 - 1/3*m1
1/3*m2 = 2/3*m1
m2 = 2m1
From this we can conclude that the mass of cart 2 is twice that of the mass of cart 1.
To learn more about inelastic collision visit:
brainly.com/question/14521843
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