Answer:
k1 + k2
Explanation:
Spring 1 has spring constant k1
Spring 2 has spring constant k2
After being applied by the same force, it is clearly mentioned that spring are extended by the same amount i.e. extension of spring 1 is equal to extension of spring 2.
x1 = x2
Since the force exerted to each spring might be different, let's assume F1 for spring 1 and F2 for spring 2. Hence the equations of spring constant for both springs are
k1 = F1/x -> F1 =k1*x
k2 = F2/x -> F2 =k2*x
While F = F1 + F2
Substitute equation of F1 and F2 into the equation of sum of forces
F = F1 + F2
F = k1*x + k2*x
= x(k1 + k2)
Note that this is applicable because both spring have the same extension of x (I repeat, EXTENTION, not length of the spring)
Considering the general equation of spring forces (Hooke's Law) F = kx,
The effective spring constant for the system is k1 + k2
Lolilolololilolollololililili
<em>It is a series circuit.</em>
it will move the object if you apply force, because of that it will stay the same with newton's law.
The more energy orbits the radiation jumps the more energy it has. So if the frequency stays the same each time then the wavelength will get longer if there is more energy.
In this case the situation in which the radiation jumps the most energy orbits is when: the electron jumps from the fourth orbit to the first orbit. This will emit the longest wavelength
