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4 years ago

According to Le Châtelier's principle, what happens if heat is added to a system?

Chemistry

1 answer:

Dmitrij [34]4 years ago

5 0

Answer: Option (B) is the correct answer.

Explanation:

According to Le Chatelier principle, when a system is in equilibrium then any change in the reaction will shift the equilibrium in a direction which is opposing the change.

For example, when heat is added to a system the molecules will gain kinetic energy. So, rate of reaction will increase hence, product formation will increase but equilibrium will shift in the opposite direction.

Hence, we can conclude that according to Le Chatelier's principle, the reaction shifts to remove the heat if heat is added to a system.

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Which is a binary ionic compound? A. MgCl2 B. C6H12O6 C. CO2 D. PO43- E. CH4

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3 years ago

2. What are two types of local winds?

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3 years ago

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Given the following two quantities: 0.50 mol of CH4 and 1.0 mol of HCl,

Vinil7 [7]

Answer:

(a) HCl

(b) HCl

(d) HCl

Explanation:

<em>Given: </em>0.50 mol of CH₄ and 1.0 mol of HCl

Using stoichiometry we can calculate the answers to parts a, b, c, and d.

# of moles × Avogadro's number = # of atoms or molecules

Avogadro's number: 6.02 * 10²³

$\displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{6.02\cdot 10^2^3 \ \text{atoms CH}_4}{1 \ \text{mol CH}_4} = 3.01 \cdot 10^2^3 \ \text{atoms CH}_4$
$\displaystyle 1.0\ \text{mol HCl} \cdot \frac{6.02\cdot 10^2^3 \ \text{atoms HCl}}{1 \ \text{mol HCl}} = 6.02 \cdot 10^2^3 \ \text{atoms HCl}$

HCl has more atoms than CH₄.

This is calculated the same way as Part (a); HCl has more molecules than CH₄.

Molar mass of CH₄ = 16.04 g/mol

Molar mass of HCl = 36.458 g/mol

$\displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{16.04 \ \text{g CH}_4}{1 \ \text{mol CH}_4} = 8.02 \ \text{g CH}_4$
$\displaystyle 1.0\ \text{mol HCl} \cdot \frac{36.458 \ \text{g HCl}}{1 \ \text{mol HCl}} = 36.458 \ \text{g HCl}$

HCl has a greater mass than CH₄.

Assuming STP:

Molar volume of any gas at STP is 22.4 L/mol.

$\displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{22.4 \ \text{L CH}_4}{1 \ \text{mol CH}_4} = 11.2 \ \text{L CH}_4$
$\displaystyle 1.0\ \text{mol HCl} \cdot \frac{22.4 \ \text{L HCl}}{1 \ \text{mol HCl}} = 22.4 \ \text{L HCl}$

HCl has a greater volume than CH₄.

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3 years ago