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kiruha [24]
4 years ago
12

Ifferences in elevation are best shown using a _____.

Physics
1 answer:
PolarNik [594]4 years ago
8 0
Differences in elevation are best shown using a topographic map. This is because it uses a large-scale detail representation of the the Earth's relief, mostly by using contour lines. Some traditional definitions show both natural and manmade features, which make it the best map to use when dealing with elevations.
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. The free throw line in basketball is 4.57 m (15 ft) from the basket, which is 3.05 m (10 ft) above the floor. A player standin
pentagon [3]

Answer:

\theta = 67.22 degree

Explanation:

Let say the ball is projected at an angle with horizontal

So here two components of the velocity of the ball is given as

v_x = 8.15 cos\theta

v_y = 8.15 sin\theta

now the displacement in x direction is given as

x = v_x t

4.57 = (8.15 cos\theta)t

in y direction it is given as

y = y_o + v_y t - \frac{1}{2}gt^2

3.05 = 2.44 + (8.15 sin\theta) t - 4.9 t^2

now from above two equations

0.61 = 4.57 tan\theta - 4.9(\frac{4.57}{8.15 cos\theta})^2

0.61 = 4.57 tan\theta - 1.54(1 + tan^2\theta)

1.54 tan^2\theta - 4.57 tan\theta + 2.15 = 0

\theta = 67.22 degree

7 0
3 years ago
Elements in which family are most likely to have properties associated with
Elena-2011 [213]

Answer:  As with all metals, the alkali metals are malleable, ductile, and are good conductors of heat and electricity. The alkali metals are softer than most other metals.

Alkaline earth metals

The alkaline earth elements are metallic elements found in the second group of the periodic table

Explanation:

5 0
4 years ago
Calcite (CaCO_3) is a crystal with abnormally large birefringence. The index of refraction for light with electric field paralle
katrin2010 [14]

Answer:

(a) 42.28°

(b) 37.08°

Explanation:

From the principle of refraction of light, when light wave travels from one medium to another medium, we have:

\frac{n_{b} }{n_{a} } = sinθ_{a}/sinθ_{b}

In the given problem, we are given the refractive indices of light which are parallel and perpendicular to the axis of the optical lens as 1.4864 and 1.6584 respectively.

For critical angle θ_{a} = θ_{c}, θ_{b} = 90°; n_{b} = 1

(a) n_{a} = 1.4864

\frac{1 }{1.4864 } = sinθ_{c}/sin90°

0.6728 = sinθ_{c}θ[tex]_{c} = sin^(-1) 0.6728 = 42.28°(b) [tex]n_{a} = 1.6584

\frac{1 }{1.6584} = sinθ_{c}/sin90°

0.60299 = sinθ[tex]_{c}

θ[tex]_{c} = sin^(-1) 0.60299 = 37.08°

7 0
4 years ago
Which statements describe processes involved in the accretion of planetesimals and protoplanets? Check all that apply.
MakcuM [25]

Answer:

The correct options are;

Both involve the formation of solid particles from nebular materials

Both involve the work of gravitational push on nebular materials

Explanation:

Planetesimals are thought to be the product of grains of cosmic dusts that are found in the debris and protoplanetary discs, such that hundreds of planet forming embrayos are considered to be the result of the collisions of planetesimals that collide with each other to form larger embrayos

Protoplanets is a large planetary body with a stratified interior due to internal melting that has taken place. They originate in the protoplanetary discs from the collision of planetesimals that are up to a kilometer in size.

4 0
3 years ago
Read 2 more answers
In Trial II, the same spring is used as in Trial I. Let us use this information to find the suspended mass in Trial II. Use 0.51
Masteriza [31]

Answer:

M_2=0.79kg

Explanation:

From the question we are told that:

Period T=0.517s

Trial 1

Spring constant \mu=117N/m

Period T_1=0.37

Mass m=0.400kg

Trial 2

Period T_2=0.52

Generally the equation for Spring Constant  is mathematically given by

\mu=\frac{4 \pi^2 M}{T^2}

Since

\mu _1=\mu_2

Therefore

\frac{4 \pi^2 M_1}{T_1^2}=\frac{4 \pi^2 M_2}{T_2^2}

M_2=M_1*(\frac{T_2}{T_1})^2

M_2=0.400*(\frac{0.52}{0.37}})^2

M_2=0.79kg

5 0
3 years ago
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