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elixir [45]
3 years ago
10

Match each polynomial function w/ one of its factors.

Mathematics
2 answers:
gladu [14]3 years ago
8 0

Answer:

See below in bold.

Step-by-step explanation:

The first one looks like  x + 3 might be a factor. By the Factor Theorem :To check we plug in x = -3 to see if the f(3) = 0.

f(3) = -27 - 27 + 39 + 15 = 0

So x+3 is a factor of  x^3 - 3x^2 - 13x + 15.

x^3 - 2x^2 - x + 2

Because of the last term +2 , it looks like x - 2 might be a factor of this so we evaluate f(2)

f(2) = 8 - 8 - 2 + 2 = 0

So x - 2 is a factor of x^3 - 2x^2 - x + 2 .

x^4 + 3x^3 - 8x^2 + 5x  - 25.

Because of  the - 25 x + 5 could be a factor so try f(-5)

= (-5)^4 - 3* -125 - 8*25 + 5 * -5 - 25  = 0

So x + 5 is a factor of  x^4 + 3x^3 - 8x^2 + 5x  - 25.

Finally we check if (x + 4) is a factor of -x^3 + 13x - 12 :

f(-4) = - (-4)^3 + 13*-4 - 12 = 0.

So x + 4 is a factor of  -x^3 + 13x - 12.

ololo11 [35]3 years ago
4 0

Answer: 1 goes with 2 4 goes with 3

Step-by-step explanation:

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45 points for first most detailed / accurate answer:
Bas_tet [7]
A.) Since there are no restrictions as to the dimensions of the candle except that their volumes must equal 1 cubic foot and that each must be a cylinder, we have the freedom to decide the candles' dimensions. 

I decided to have the candles equal in volume. So, 1 cubic foot divided by 8 gives us 0.125 cubic foot, 216 in cubic inches.

With each candle having a volume of 216 cubic inches, I assign a radius to each: 0.5 in, 1.0 in, 1.5 in, 2.0 in, 2.5 in, 3.0 in, 3.5 in, and 4.0 in. Then, using the formula of the volume of a cylinder, which is:

V=pi(r^2)(h)

we then solve the corresponding height per candle. Let us let the value of pi be 3.14.

Hence, we will have the following heights (expressed to the nearest hundredths) for each of the radius: for 

r=2.5 in: h=11.01 in
r=3.0 in: h= 7.64 in
r=3.5 in: h= 5.62 in
r=4.0 in: h= 4.30 in
r=4.5 in: h= 3.40 in
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7 0
2 years ago
Evaluate the function g(x) = 2x2 + 3x – 5 for the input values -2, 0, and 3.
Roman55 [17]

Evaluate the function

g(x) = 2x2 + 3x – 5 for the input values -2, 0, and 3.

This is tedious math work but necessary to sharpen your skills.

Let x = -2

g(-2) = 2(-2)^2 + 3(-2) – 5

g(-2) = 2(4) - 6 - 5

g(-2) = 8 - 11

g(-2) = -3

Now let x = 0 and repeat the process.

g(0) = 2(0)^2 + 3(0) - 5

g(0) = 0 + 0 - 5

g(0) = -5

Lastly, let x = 3.

g(3) = 2(3)^2 + 3(3) - 5

g(3) = 2(9) + 9 - 5

g(3) = 18 + 9 - 5

g(3) = 27 - 5

g(3) = 22

Did you follow through each step?

4 0
3 years ago
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